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Alecsey [184]
3 years ago
7

Jill Hartman earns $750 per week, plus 3% of sales in excess of $6500. if Jill sells $25000 in the first week her earnings are ?

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
7 0
The answer is going to be: answer B.

Hope this helps =D

Olegator [25]3 years ago
3 0

Answer:

It would be d) $1305

Step-by-step explanation:

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Solve the following system of equations.<br>2x + 5y = 19<br>x - 2y = - 4​
garri49 [273]

Answer:

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can you help me please ​
alexira [117]

Answer:

Please check the explanation.

Step-by-step explanation:

Given that

|v|=38

Ф = 120°

<u>Finding the horizontal component</u>

The horizontal component can be obtained using the formula

Vx = |v| cos Ф

     = 38 cos 120°

     = 38 (-0.5)

      = -19

Thus, the  horizontal component is:

Vx = -19

<u>Finding the vertical component</u>

The vertical component can be obtained using the formula

Vy = |v| sin Ф

    = 38 sin 120°

    = 38 (0.86)

    = 32.68

Thus, the vertical component is:

Vy = -19

  • A vector 'v' with magnitude |v| and direction Ф can be written as:

v = |v| cos Ф i + |v| sin Ф j

As

|v|=38

Ф = 120°

Thus, the vector is

v = 38 cos 120° i + 38 sin 120° j

or

v = -19 i + 32.68 j

5 0
2 years ago
Write the equation of a line with a slope of −2 and a y-intercept of 5
Aleonysh [2.5K]
Y or f(x) = -2x+5

the slope goes with the variable (x) and when the value of x is entered it makes a line, and the y-intercept is next to show where the point is on the y - line
8 0
3 years ago
Please answer right away
irina1246 [14]

Answer:

$29000 with a margin of error of $5000

Step-by-step explanation:

We have that the midpoint between the given values ​​is

(X1+X2) / 2 = ($34000+$24000)/2 = $29000

We have that the midpoint between the given values ​​would be

(X2-X1)/2=($34000-$24000)/2=$10000/2=$5000

So I can write that approach as $29000 with a margin of error of $5000

Done

5 0
3 years ago
​Joe's annual income has been increasing each year by the same dollar amount. The first year his income was ​$17 comma 90017,900
Vedmedyk [2.9K]

Answer:

In 17th year, his income was $30,700.

Step-by-step explanation:

It is given that the income has been increasing each year by the same dollar amount. It means it is linear function.

Income in first year = $17,900

Income in 4th year = $20,300

Let y be the income at x year.

It means the line passes through the point (1,17900) and (4,20300).

If a line passes through two points (x_1,y_1) and (x_2,y_2), then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line is

y-17900=\frac{20300-17900}{4-1}(x-1)

y-17900=\frac{2400}{3}(x-1)

y-17900=800(x-1)

y-17900=800x-800

Add 17900 on both sides.

y=800x-800+17900

y=800x+17100

The income equation is y=800x+17100.

Substitute y=30,700 in the above equation.

30700=800x+17100

Subtract 17100 from both sides.

30700-17100=800x

13600=800x

Divide both sides by 800.

\frac{13600}{800}=x

17=x

Therefore, in 17th year his income was $30,700.

5 0
3 years ago
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