-5,3,-2,1 on a number line
<-|----|----|----|----|----|----|----|----|->
-5 -2 0 1 3
Answer:
3 days
Step-by-step explanation:
This can be seen under Schedule management (Initiating)
Project float is simply the difference between the completion period externally imposed and the estimated time duration of the project (usually this is equal to the critical path length). The difference in this case is 0 because
Externally imposed project date = 75 days
Estimated duration of project = 75 days
Hence, a difference in these will be 0
However, a standard deviation of 3 days was giving (This implies that there is a +/- 3 days in the critical path from the estimated project duration)
.
Hence the maximum float in this case will be 0 + 3 = 3 days
In terms of points, a point that is coplanar is one that lies anywhere on the given plane while a point that is collinear is a point that lies anywhere on the given line.
Slope point form :
To put in slope point form, label any of the points as either X1,y1 and X and y, then plug in those values into the following equation form.
Y - y1 = m(X-X1)
But before, we must solve for the m value or slope.
M = y2-y1/x2-X1
M = 5/2 - -1/2 / -1/2 - 3/2.
M = 5/2 + 1/2 / -(1/2+3/2)
M = 6/2 / -(4/2)
M = 3/-2
Now we can place it in slope point and also in standard form of a line.
Y-y1 = m(X -X1)
Y - -1/2 = -3/2(X - 3/2)
Y + 1/2 = -3/2(X - 3/2)
This is in slope point form.
Y + 1/2 = -3/2x + 9/4
Y + 1/2 - 1/2 = -3/2x + 9/4 - 1/2
1/2 = 2/4
Y = -3/2x + 7/4
-3/2x = -6/4x
Y = -6/4x + 7/4
Y • 4 = 4( -6/4 X + 7/4)
4y = -6x + 7
4y + 6x = -6x + 6x +7
6x + 4y = 7
This is in standard form. If you have any questions of the steps just ask.
