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Jlenok [28]
2 years ago
11

Find the value of the following (-42) + 15 + (-63) can someone say this and fast

Mathematics
2 answers:
Karolina [17]2 years ago
6 0

\\ \sf\longmapsto (-42)+15+(-63)

\\ \sf\longmapsto -42+15+(-63)

\\ \sf\longmapsto -27+(-63)

\\ \sf\longmapsto -27-63

\\ \sf\longmapsto -90

Alexxandr [17]2 years ago
6 0

Answer:

42 + 15 + (-63) = -90

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

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antwan is looking to get an apartment that cost $650 per month. How much does he need to make per year
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the answer is 7800

Step-by-step explanation:to get the answer you need to multiply 650 times how many months there are in a year which are 12 so 650 times 12 equals 7800 I hope this helped you.

                                                                             

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What's the answer to 3.75 ✖️4
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4 0
3 years ago
Read 2 more answers
Solve the simultaneous equation x+y/4=1/2 and x-3y/3=2
Feliz [49]

Answer:

x+y/4 = 1/2

x-3y/3 = 2

move variables to one side:

multiply the first equation by 4 to get: x+y =2

and the second equation by 3 to get: x-3y =6

then subtract the equations to cancel out x:

 x+y = 2

- x-3y = 6

then u get

y--3y = 2-6

4y = -4

y=-1

substitute to solve for x:

x-1 / 4 =1/2

x-1 = 2

x=3

check:

3+-1

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correct!!!

3 0
3 years ago
Read 2 more answers
Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En
ArbitrLikvidat [17]

Answer:

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, c) x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right), y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right).

Step-by-step explanation:

The equation of the circle is:

x^{2} + (y-1)^{2} = 16

After some algebraic and trigonometric handling:

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t

Where:

\frac{x}{4} = \cos t

\frac{y-1}{4} = \sin t

Finally,

x = 4\cdot \cos t

y = 1 + 4\cdot \sin t

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

c) x = 4\cdot \cos t'', y = 1 + 4\cdot \sin t''

Where:

4\cdot \cos t' = 0

1 + 4\cdot \sin t' = 5

The solution is t' = \frac{\pi}{2}

The parametric equations are:

x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right)

y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)

7 0
3 years ago
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