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3 years ago

15

A pentagon has angle measures of 105°, 101°, 112° and 113°. What must the fifth angle measure?

2 answers:

Taya2010 [7]3 years ago

8 0

Add them. Pentagram interior angle is 540. 105+101+112+113=431. 540-431=109 Hence, 109 is the answer. Please brainliest.

babymother [125]3 years ago

7 0

Answer:

109

Step-by-step explanation:

Pentagon can be represented with 3 triangles:

A+B+C+D+E=3×180

105+101+112+113+E=540 => E=109

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1<br> 4<br> Joey enlarged a 3-inch by 5-inch photograph on a copy machine. He enlarged it four times. The table below<br> shows

lozanna [386]

Answer:

3) 5.4

Step-by-step explanation:

Given two points (x1, f(x1)) and (x2, f(x2)), the average rate of change is computed as follows:

[f(x2) - f(x1)]/[x2 - x1]

From the original photograph to the fourth enlargement, the points are (0, 15) and (4, 36.6). Replacing into the equation we get:

[36.6 - 15]/[4 - 0] = 5.4

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3 years ago

Explain how you can use base 10 blocks to find one. 54+2.37

jasenka [17]

So you mean add 54+2.37? Well, I do know that the answer to 53+2.37= 2.90. I hope I helped, even if I only helped by an inch.

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3 years ago

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Help shaded parts need answers

Andrej [43]

Answer:

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Step-by-step explanation:

4 0

3 years ago

A triangle has a base of 54 cm. The height is unknown. Complete the equation that can be used to find the area, A, of the triang

Nookie1986 [14]

Answer:

Step-by-step explanation:

area=1/2×base×height

A=1/2×54×h=27h

4 0

3 years ago