The solutions can be 0,1.5,1/2,1,0.03.
Step-by-step explanation:
area of the trapezoid = area of the 2 triangles +
area of the rectangle
i) area of triangle on left:
a = ½ bh
a = ½ × 2 × 9
a = 9 in²
ii) area of triangle on right:
a = ½ bh
a = ½ × 2 × 9
a = 9 in²
iii) area of rectangle = length × width
a = l × w
a = 12 × 9
a = 108 in²
iv) area of trapezoid = 9 + 9 + 108
= 126 in²
hope this helps you!
-s.
Answer:
what what is the question
9514 1404 393
Answer:
24.885 in²
Step-by-step explanation:
Use the formula for the area of a triangle.
A = 1/2bh . . . . . . . where b is the base length and h is the height perpendicular to the base
A = 1/2(7.9 in)(6.3 in) = 24.885 in²
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<em>Additional comment</em>
The given side lengths cannot form a triangle, as the side shown as 14.7 is too long for the ends of the other segments to connect to. The attachment shows that side should be 11.97 in.
The volume of a cube is side length cubed (s^3)
So if you know the volume then take the cube root of 1/512... which is 1/8
So each side of the cube is 1/8.
There are 6 congruent sides on a cube (picture a “dice”). Do the area of each side would be (1/8)(1/8)= 1/64 then multiply that area by 6 and reduce ... you get 6/64 = 3/32 for the surface area