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Ulleksa [173]
3 years ago
14

Find the result when -18 M -4 is added to 4m - 14

Mathematics
1 answer:
scoray [572]3 years ago
7 0

Answer:

-14m - 18

Step-by-step explanation:

Hi there!

To find the answer, we will first have to merge the expressions.

-18m - 4 + 4m - 14

To simplify this, we have to combine like terms.

-18m and 4m can be added together to create -14m

-4 and -14 can be added together to make -18.

Now that our terms are simplified, the expression becomes -14m - 18.

Hope this helped!

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Find the value of y for the given value of x. Round to the nearest hundredth. y = 15 + 3 ln x; x = 7.2
Nikolay [14]

Answer:

y = 20.922

Step-by-step explanation:

Simply plug in <em>x</em> and evaluate:

y = 15 + 3ln(7.2)

Only way to calculate ln is to plug into a calc:

We should get 20.9222 as our answer.

7 0
3 years ago
Find the volume of this square pyramid to the nearest tenth.
Hitman42 [59]
Formula:

V = 1/3 * b^2 * h

Plug in what we know:

V = 1/3 * 7^2 * 16

Simplify the exponent:

V = 1/3 * 49 * 16

Multiply all 3 numbers together:

V = 261.3cm^3
7 0
3 years ago
Write the equation of the line that passes through (0,5) and is perpendicular to the line x = 3.
Alona [7]

Answer:

(0,5)x3=(15,5)

Step-by-step explanation:

3 0
3 years ago
The core melt- down and explosions at the nuclear reactor in Chernobyl in 1986 released large amounts of strontium-90, which dec
elena-14-01-66 [18.8K]

If S(t) is the amount of strontium-90 present in the area in year t, and it decays at a rate of 2.5% per year, then

S(t+1)=(1-0.025)S(t)=0.975S(t)

Let S(0)=s be the starting amount immediately after the nuclear reactor explodes. Then

S(t+1)=0.975S(t)=0.975^2S(t-1)=0.975^3S(t-2)=\cdots=0.975^{t+1}S(0)

or simply

S(t)=0.975^ts

So that after 50 years, the amount of strontium-90 that remains is approximately

S(50)=0.975^{50}s\approx0.282s

or about 28% of the original amount.

We can confirm this another way; recall the exponential decay formula,

S(t)=se^{kt}

where t is measured in years. We're told that 2.5% of the starting amount s decays after 1 year, so that

0.975s=se^k\implies k=\ln0.975

Then after 50 years, we have

S(50)=se^{50k}\approx0.282s

5 0
3 years ago
Please help. Offering all the points I have.
Simora [160]

The most specific name of the quadrilateral that's is drawn in the picture is a rhombus.

<h3>What is a rhombus?</h3>

It should be noted that a rhombus simony means a quadrilateral that has four sides and the total angles are 360°.

Also, from the information given, it can be depicted that the lengths are congruent and that the opposite sides are parallel.

Learn more about rhombus on:

brainly.com/question/20627264

#SPJ1

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2 years ago
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