Answer:
![C(x) = \frac{x^4}{4}-3x^2+3,000](https://tex.z-dn.net/?f=C%28x%29%20%3D%20%5Cfrac%7Bx%5E4%7D%7B4%7D-3x%5E2%2B3%2C000)
Step-by-step explanation:
The marginal cost function, C'(x), is the derivate of the cost function, C(x).
Therefore, we can obtain the cost function by finding the integral of the marginal cost function:
![C(x) = \int\ {C'(x)} \, dx \\C(x) = \int\ {(x^3-6x)} \, dx \\C(x) = \frac{1}{4} x^4-3x^2+a](https://tex.z-dn.net/?f=C%28x%29%20%3D%20%5Cint%5C%20%7BC%27%28x%29%7D%20%5C%2C%20dx%20%5C%5CC%28x%29%20%3D%20%5Cint%5C%20%7B%28x%5E3-6x%29%7D%20%5C%2C%20dx%20%5C%5CC%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%20x%5E4-3x%5E2%2Ba)
Where 'a' is a constant and represents fixed costs. If fixed costs are $3,000, the cost function is:
![C(x) = \frac{x^4}{4}-3x^2+3,000](https://tex.z-dn.net/?f=C%28x%29%20%3D%20%5Cfrac%7Bx%5E4%7D%7B4%7D-3x%5E2%2B3%2C000)
Answer:
5,-3
Step-by-step explanation:
Answer:
4.5 or 4 1/2
Step-by-step explanation:
Answer:
Step-by-step explanation:
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let be the number of pets and is the probability of owning the number of pets
Answer:
Hi there
Your answer is
10 Bunches
Step-by-step explanation:
4 bunches= 8$
/8 for how many bunches per 1$
.5bunches= 1$
*20
10bunches=20$