The slope of the line

-2(3 + c) = 16 what is the value of c is a solution to the equation

lana [24]

Answer:

-11

Step-by-step explanation:

Simplify

4 0

2 years ago

Read 2 more answers

How do i write, Two increased by three equals the quotient of ten and two. Use x to represent any unknown number?

inn [45]

Answer:

$2+3=\frac{10}{2}$

Step-by-step explanation:

we know that

The phrase " Two increased by three equals the quotient of ten and two" is equal to the algebraic expression

$2+3=\frac{10}{2}$

$5=5$ -----> is true

7 0

2 years ago

there are 9 students in a class: 7 boys and 2 girls. if the teacher picks a group of 3. at random, what is the probability. that

timurjin [86]

There is a 1 out of 3 chance of a full boy group

6 0

3 years ago

Read 2 more answers

According to an airline, flights on a certain route are on time 80 % of the time. suppose 10 flights are randomly selected and

natulia [17]

(a) This is a binomial experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
(b) Using the formula:
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
(c) Fewer than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.

6 0

2 years ago

Help asap pls

Svet_ta [14]

Answer:

Eating dinner and eating dessert are dependent events because

P(dinner) . P(dessert) = 0.9 × 0.6 = 0.54 which is not equal to

P(dinner and desert) = 0.5 ⇒ answer A

Step-by-step explanation:

* Lets study the meaning independent and dependent probability

- Two events are independent if the result of the second event is not

affected by the result of the first event

- If A and B are independent events, the probability of both events

is the product of the probabilities of the both events

- P (A and B) = P(A) · P(B)

* Lets solve the question

∵ There is a 90% chance that a person eats dinner

∴ P(eating dinner) = 90/100 = 0.9

∵ There is a 60% chance a person eats dessert

∴ P(eating dessert) = 60/100 = 0.6

- If eating dinner and dating dessert are independent events, then

probability of both events is the product of the probabilities of the

both events

∵ P(eating dinner and dessert) = P(eating dinner) . P(eating dessert)

∴ P(eating dinner and dessert) = 0.9 × 0.6 = 0.54

∵ There is a 50% chance the person will eat dinner and dessert

∴ P(eating dinner and dessert) = 50/100 = 0.5

∵ P(eating dinner and dessert) ≠ P(eating dinner) . P(eating dessert)

∴ Eating dinner and eating dessert are dependent events because

P(dinner) . P(dessert) = 0.9 × 0.6 = 0.54 which is not equal to

P(dinner and desert) = 0.5

8 0

2 years ago

The slope of the line​

The slope of the line