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Ksivusya [100]
3 years ago
6

According to chebyshev's theorem, the maximum proportion of data values from a data set that are more than 2 standard deviations

from the mean is _________.
Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0
<span>All you have to do is learn Chebyshev's theorem in terms of k, then substitute 2 for k. Here is Chebyshev's theorem in terms of k: According to Chebyshev's theorem, the proportion of values from a data set that is further than standard deviations from the mean is at most . Then when you plug in 2 for k, you get: According to Chebyshev's theorem, the proportion of values from a data set that is further than standard deviations from the mean is at most . or writing for , According to Chebyshev's theorem, the proportion of values from a data set that is further than standard deviations from the mean is at most . Or if you prefer a decimal answer: According to Chebyshev's theorem, the proportion of values from a data set that is further than standard deviations from the mean is at most . Or if you prefer a percent answer: According to Chebyshev's theorem, the proportion of values from a data set that is further than standard deviations from the mean is at most %. </span>
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In a chemistry lab an experiment requires 500ml of one ingredient to be mixed with 1000 mL of another. how many ounces is the so
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Find the minimum and maximum of f(x, y, z) = y + 4z subject to two constraints, 2x + z = 4 and x2 + y2 = 1. g
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L(x,y,z,\lambda_1,\lambda_2)=y+4z+\lambda_1(2x+z-4)+\lambda_2(x^2+y^2-1)

L_x=2\lambda_1+2\lambda_2 x=0\implies\lambda_1+\lambda_2x=0
L_y=1+2\lambda_2y=0
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x^2+y^2=1\implies (-8y)^2+y^2=65y^2=1\implies y=\pm\dfrac1{\sqrt{65}}
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At these points, we respectively have a maximum of 16+\sqrt{65} and a minimum of 16-\sqrt{65}.
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