Answer:
We are given an area and three different widths and we need to determine the corresponding length and perimeter.
The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards. This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.
The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards. This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.
The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10. This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.
Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.
<u><em>Hope this helps!</em></u>
Answer:
You have to have the graph to answer it.
Step-by-step explanation:
Answer:
x² - 4
Step-by-step explanation:
Step 1: Write expression
(x + 2)(x - 2)
Step 2: FOIL
x² + 2x - 2x - 4
Step 3: Combine like terms
x² - 4
First of all you need to put a table up so people know what you're talking about, but It just so happens I'm a student as well, so the answer is 5 because the question ask how many people are 12 years or older there are 3 12-14 kids and 2 15-17 kids so 3+2=5
Answer:
Step-by-step explanation:
Start
<F = <Q Given
<GPF = <RPQ Vertically opposite angles
<FGP = <QRP A triangle has 180 degrees. 2 equal angles means the third pair must be equal
Triangle GPF ~ Triangle RPQ AAA
end
I don't see any way to make these triangles similar except by stating the statement and why it is so. There really are no yes / no choices. If you get another answer, choose it.
20
JL/LE = 90/27 Given
KL /LD = 90/27 Given
<JLK = <DLK Vertically opposite
Are the ratios equal Yes Then is the angle included Yes
Then the triangles are similar.
Are the ratios not equal No then the triangles cannot be similar
Is the angle not included Then similarity cannot be proved.
ΔJLK ≈ ΔDLK Equal Ratios and included angle === similarity