(x2-y1)²+(2xy)1 =
x⁴-2x²y²+y⁴+4x²y² =
x⁴+2x²y²+y⁴=
(x²+y²)²
Answer:
An acute angle is less than 90°.
An obtuse angle is more than 90°.
Step-by-step explanation:
Sorry if wrong didn't really get the question I'm a little slow
Answer:
7.5s
1.6666 repeating or 1.67 m/s²
Step-by-step explanation:
the equation you have to use is Vfinal=Vstart+acceleration•time
(I'm gonna simplify to Vf=Vs+at)
so you gotta rework it for the two equations
for the first equation you need time so take Vf=Vs+at and subtract Vs on both sides to get Vf–Vs=at
then divide acceleration on both sides to get t=(Vf–Vs)/a
for the second problem equation need the equation a=(Vf–Vs)/t (just divide time on both sides instead of acceleration)
so you the plug in
(I don't put the units in to the problem unless needed)
1. t=(Vf–Vs)/a to t=(0–30)/-4.0
t= -30/-4.0
t=7.5 seconds
2. a=(Vf–Vs)/t to a=(10–0)/6.0
a= 10/6.0
a= 1.67m/s²
(I'm assuming the that for number two they started at rest so it would be 0m/s for velocity start)
L = 2W
A = 50
A = L x W
50 = 2W x W
50 = 2W^2
W^2 = 25
W = 5
so L = 2W = 2(5) = 10
P = 2(L+W)
P = 2(10+5)
P = 2(15)
P = 30
answer
P = 30 in
