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castortr0y [4]
2 years ago
14

A person is playing a video game where the number of aliens that appear on a level triples each time from the previous level. Le

vels start at 0 and on Level 0 only 5 aliens appear.
A.)How many aliens appear on the Level 2?
B.) What formula is used to find each number of aliens
Mathematics
1 answer:
exis [7]2 years ago
3 0

Answer:

45

A=5(3L) <-not fully sure if correct

A=aliens

L=levels

Step-by-step explanation:

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Help ( i need to show my work)!!!
hodyreva [135]

its 7 because 7*7=49 and 49*7=343

so the cube root of 343 would be 7

8 0
3 years ago
Can you all please help me with problems 6 through 10? Please don’t use for points I’m extremely stressed and need help
patriot [66]

Answer:

See below.

Step-by-step explanation:

6.) (5)/6 ≤ 1 (Yes)

7.) 1.4(11) > 16

    15.4 > 16 (No)

8.) 11.1 + 9.8 ≥ 21.01

    20.9 ≥ 21.01 (No)

9.) 2.5 < (90)/30

    2.5 < 3 (Yes)

10.) 1/2 > 3(1/6)

      1/2 > 1/2 (No)

11.) 2.16 ≥ 3(0.6) - 0.5

     2.16 ≥ 1.8 - 0.5

     2.16 ≥ 1.3 (Yes)

12.) x < 2 (x is less than 2.)

13.) x ≥ -1 (x is greater than or equal to -1.)

5 0
3 years ago
Read 2 more answers
30 POINTS!!!!!
Tomtit [17]
Teh answer is 4 cm^2
5 0
3 years ago
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When you add 18 to 1/4 of a number. I dont need to solve it but i need to make it an equation. x equals a number. so would the a
erik [133]
Yes, that answer is right, good job.
5 0
3 years ago
Determine the formula for the nth term of the sequence:<br>-2,1,7,25,79,...​
rodikova [14]

A plausible guess might be that the sequence is formed by a degree-4* polynomial,

x_n = a n^4 + b n^3 + c n^2 + d n + e

From the given known values of the sequence, we have

\begin{cases}a+b+c+d+e = -2 \\ 16 a + 8 b + 4 c + 2 d + e = 1 \\ 81 a + 27 b + 9 c + 3 d + e = 7 \\ 256 a + 64 b + 16 c + 4 d + e = 25 \\ 625 a + 125 b + 25 c + 5 d + e = 79\end{cases}

Solving the system yields coefficients

a=\dfrac58, b=-\dfrac{19}4, c=\dfrac{115}8, d = -\dfrac{65}4, e=4

so that the n-th term in the sequence might be

\displaystyle x_n = \boxed{\frac{5 n^4}{8}-\frac{19 n^3}{4}+\frac{115 n^2}{8}-\frac{65 n}{4}+4}

Then the next few terms in the sequence could very well be

\{-2, 1, 7, 25, 79, 208, 466, 922, 1660, 2779, \ldots\}

It would be much easier to confirm this had the given sequence provided just one more term...

* Why degree-4? This rests on the assumption that the higher-order forward differences of \{x_n\} eventually form a constant sequence. But we only have enough information to find one term in the sequence of 4th-order differences. Denote the k-th-order forward differences of \{x_n\} by \Delta^{k}\{x_n\}. Then

• 1st-order differences:

\Delta\{x_n\} = \{1-(-2), 7-1, 25-7, 79-25,\ldots\} = \{3,6,18,54,\ldots\}

• 2nd-order differences:

\Delta^2\{x_n\} = \{6-3,18-6,54-18,\ldots\} = \{3,12,36,\ldots\}

• 3rd-order differences:

\Delta^3\{x_n\} = \{12-3, 36-12,\ldots\} = \{9,24,\ldots\}

• 4th-order differences:

\Delta^4\{x_n\} = \{24-9,\ldots\} = \{15,\ldots\}

From here I made the assumption that \Delta^4\{x_n\} is the constant sequence {15, 15, 15, …}. This implies \Delta^3\{x_n\} forms an arithmetic/linear sequence, which implies \Delta^2\{x_n\} forms a quadratic sequence, and so on up \{x_n\} forming a quartic sequence. Then we can use the method of undetermined coefficients to find it.

5 0
2 years ago
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