Answer:
Answer is D 5x-y>= 1 :)
Step-by-step explanation:
Answer:
will this work or help ?
Step-by-step explanation:
The given equation governs the height versus time of the object. h(0) = 64, so the ground is considered at h = 0. The question is at what time is h = 0? So, set h = 0 and solve for t.
-16t^2 + 48t + 64 = 0
We can divide both sides of this equation by -16 for simpler numbers. We get
t^2 - 3t - 4 = 0
We can factor this equation:
(t - 4)(t + 1) = 0
So, t = 4 and t = -1 are solutions.
But, time must be positive, so t = -1 makes no sense, so we discard it. This leaves
t = 4 sec.
Given:
The graph of a system of equations.
To find:
The solution of the given system of equations.
Solution:
If a system of equations has two equations, then the intersection points of the graphs of these two equations are the solutions for the system of equations.
From the given graph it is clear that the graph of both line intersect each other at point 
.
Therefore, the solution is .
Answer:
1e+12 is the answer lol dont worry bout it
