LHS ⇒ RHS:
Identities:
[1] cos(2A) = 2cos²(A) - 1 = 1 - 2sin²(A)
[2] sin(2A) = 2sin(A)cos(A)
[3] sin(A + B) = sin(A)cos(B) + cos(A)sin(B)
[4] cos(A + B) = cos(A)cos(B) - sin(A)sin(B)
cos(x) - cos(x + 2Θ)
= cos(x) - (cos(x)cos(2Θ) - sin(x)sin(2Θ)) [4]
= cos(x) - cos(x)(1 - 2sin²(Θ)) + sin(x)(2sin(Θ)cos(Θ)) [1] [2]
= cos(x) - cos(x) + 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin(Θ)(sin(Θ)cos(x) + sin(x)cos(Θ))
= 2sin(Θ)sin(x + Θ)
None of them because they are all 4 blank
Step-by-step explanation:
f(x)=2(3^x)+1
f(2)=2×3²+1
=18+1
=19
is yr answer.
Answer:
- The constant in the expression is '8'.
Step-by-step explanation:
<u>The constant is a number with no variable multiplied with the constant. </u>
- In this expression, 7k has a variable 'k', which is not a constant.
- If we look at 8, we can tell that it has no variable multiplied. This is a constant.
- When we look at the 2lk and 3l, they both have variables 'lk' and 'l' respectively. They are not constants.
Hence, the constant in the expression is '8'.
Answer:
There are <u>12 outcomes</u>
Step-by-step explanation:
There are six sides on a die and 2 side on a coin so you could ether do 6 x 2.
Or you can use the tree method.
