Let the amount deposited (principal) be x, then the amount after the required time = 2x.
A = P(1 + r/n)^nt: where A is the future value = 2x, P is the principal = x, r is the rate = 0.75%, n is the number of accumulation in a year = 12, t is the number of years.
2x = x(1 + 0.0075/12)^12t
2 = (1 + 0.000625)^12t
log 2 = 12t log (1.000625)
log 2 / log (1.000625) = 12t
1109.38 = 12t
t = 92 years
Answer:
18
Step-by-step explanation:
First, I'm assuming AB=4=4x-2 was a typo and it's supposed to be AB = 4x - 2
AB=BC
AB = 4x - 2 BC = 3x + 3
4x - 2 = 3x + 3
Solve for x Add 2 to each side
4x - 2 = 3x + 3
4x - 2 + 2 = 3x + 3 + 2
4x = 3x + 5 Subtract 3x from each side.
4x - 3x = 3x- 3x + 5
4x - 3x = 5
x = 5
Now plug back in to the original equations
AB = 4x - 2 BC = 3x + 3
AB = 4 (5) - 2 BC = 3(5) + 3
AB = 20 - 2 BC = 15 + 3
AB = 18 BC = 18
So AB is 18
1. iThis is shaped like a V with its vertex at the point (0,5)
( its ( 1,7)
2. -3 <= -1-1 = =2
so its (-1, -3)
Answer:
250
Step-by-step explanation:
divide 1000 by .4
The cost of the ride varies by however many miles is driven, however the charging rate stays the same no matter how long the ride is. In the expression 0.20m + 2.00 , 2.00 is the constant as it stays the same, and 0.20 is the coefficient as is varies with however many miles are driven.
