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3 years ago

HELP please lol ill love u forever if u do this for me bestie

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

(2x - 3)(2x - 1)(2x + 1)

Step-by-step explanation:

Begin by grouping the first and second terms and the 3rd and 4th terms. Be careful to not that the 3 changes from a plus to a minus. That's because the distributive property, when applied, will change it back to a minus.

(8x^3 - 12x^2) - (2x - 3) Take out 4x^2 from the first and second terms

4x^2(2x - 3) - (2x - 3) Now treat 2x - 3 as a single term call it y

4x^2 y - y Use the distributive property to get y alone.

y(4x^2 - 1) Factor 4x^2 - 1

y(2x - 1)(2x + 1) Put 2x - 3 back for y

(2x - 3)(2x - 1)(2x + 1)

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Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI

cricket20 [7]

Answer:

The system has infinitely many solutions

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

Switch any two rows
Multiply a row by a nonzero constant
Add one row to another

To solve the following system

$\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}$

Step 1: Transform the augmented matrix to the reduced row echelon form

$\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]$

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

which corresponds to the system

$\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}$

The system has infinitely many solutions.

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

7 0

3 years ago

Someone PLSSSSSS help im timed

WARRIOR [948]

124 sq in...................

3 0

2 years ago

Read 2 more answers

Someone please help. It is easy

Juli2301 [7.4K]

Alright. So we have 2 eggs at 2.49 each. That is $4.98. We have .25 pounds cheese priced at $13.40 per pound. 13.40 x .25 = $3.35. Then we have juice at $5.49. If we add those up we get: 4.98+3.35+5.49=$13.82. Then we get $0.75 in change, so if we add $13.82 and 0.75 we get: $14.57

The answer is $14.57.
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5 0

3 years ago

Sorry last question :(

elena55 [62]

Area of rectangle=30•12=360 square meters
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6 0

3 years ago

QUIZ

marta [7]

Answer:

B (5/8 - 6/8)

Step-by-step explanation:

Since we can just multiply the second fraction by two to get a similar denominator, we just need to multiply the second fraction.

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3 years ago

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