Answer:
(2x - 3)(2x - 1)(2x + 1)
Step-by-step explanation:
Begin by grouping the first and second terms and the 3rd and 4th terms. Be careful to not that the 3 changes from a plus to a minus. That's because the distributive property, when applied, will change it back to a minus.
(8x^3 - 12x^2) - (2x - 3) Take out 4x^2 from the first and second terms
4x^2(2x - 3) - (2x - 3) Now treat 2x - 3 as a single term call it y
4x^2 y - y Use the distributive property to get y alone.
y(4x^2 - 1) Factor 4x^2 - 1
y(2x - 1)(2x + 1) Put 2x - 3 back for y
(2x - 3)(2x - 1)(2x + 1)
