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3 years ago

HELP please lol ill love u forever if u do this for me bestie

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

(2x - 3)(2x - 1)(2x + 1)

Step-by-step explanation:

Begin by grouping the first and second terms and the 3rd and 4th terms. Be careful to not that the 3 changes from a plus to a minus. That's because the distributive property, when applied, will change it back to a minus.

(8x^3 - 12x^2) - (2x - 3) Take out 4x^2 from the first and second terms

4x^2(2x - 3) - (2x - 3) Now treat 2x - 3 as a single term call it y

4x^2 y - y Use the distributive property to get y alone.

y(4x^2 - 1) Factor 4x^2 - 1

y(2x - 1)(2x + 1) Put 2x - 3 back for y

(2x - 3)(2x - 1)(2x + 1)

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$\Large\texttt{Answer}$

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So here's the big idea: fractions must have the same denominator.

If we multiply the first fraction by 2, then both fractions will have the same denominator. *

* <em>Why 2??</em>

<em />

- Because:

We need to find the least common multiple of 3 and 6, which is 6. Next, what should 3 be multiplied by to result in 6? That's right, 2.

Also, we can only multiply the denominator by 2 as long as we multiply the numerator by 2!

So that's why we multiply the whole fraction by 2

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Watch what happens

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Add the numerators

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$\bf{\cfrac{3\div3}{6\div3}}$

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Hope that helped

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