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2 years ago

6

SOMEBODY PLEASE HELP QUICK!!! WILL GIVE BRAINLIEST

1 answer:

Anna71 [15]2 years ago

3 0

Carlos is correct

Since we don't know the length of sides PR and XZ, the triangles can't be congruent by the SSS theorem or the SAS theorem, and since we don't know the measure of angles Y and Q, the triangles can't be congruent by the ASA theorem, the SAS theorem or the AAS theorem. Therefore, Carlos is correct.

Carlos is correct. Since the angles P and X are not included between PQ and RQ and XY and YZ, the SAS postulate cannot be used, since it states that the angle must be included between the sides. Unlike with ASA, where there is the AAS theorem for non-included sides, there is not SSA theorem for non-included angles, so the triangles cannot be proven to be congruent.

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igomit [66]

Answer:

4

Step-by-step explanation:

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2 years ago

Read 2 more answers

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goldfiish [28.3K]

Answer:

LEts start with 10^1

If we have positive exponent then we add zeros

10^1= 10

$10^2=100$ (Put 2 zeros because exponent is 2)

$10^3=1000$ (Put 3 zeros because exponent is 3)

$10^4=10000$ (Put 4 zeros because exponent is 4)

$10^5=100000$ (Put 5 zeros because exponent is 5)

For negative exponent , we make a fraction . we put 1 at the top always and number as the bottom

$10^{-1}=\frac{1}{10}$ (Put 1 zero at the bottom because exponent is -1)

$10^{-2}=\frac{1}{100}$ (Put 2 zeros at the bottom because exponent is -2)

$10^{-3}=\frac{1}{1000}$ (Put 3 zeros at the bottom because exponent is -3)

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2 years ago

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Svetach [21]

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2 years ago

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Katen [24]

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2 years ago

Use the graph below to estimate the solution to the system of equations shown.

Mila [183]

Answer: The second choice is answer.

Step-by-step explanation:

<h3>The first line (Blue One)</h3>

$y=-x-3$ (Slope is -1 and intercepts y at -3)

<h3>The second one (Red One)</h3>

$y=2x-8$ (Slope is 2, to find y-intercept. Substitute x = 0 then we get -8) (For x-intercept, it's 4. Just substitute y=0 to get x-intercept.)

Because there are choices, it's easy to notice.

The first one, x = -4 and almost -5 which is not right. (x is around 1 almost 2.)

The second one, x = 1 and almost 2 is right.

The third one, x = -1 and almost -2 is not right (The intersection isn't even at -1 or any negative number for x-axis.)

The fourth one, just like the first one... x = 4 almost 5

<h3>Or solve the equations.</h3>

$y=-x-3\\y=2x-8$

Substitute y=2x-8 in y=-x-3

$2x-8=-x-3\\2x-8+x+3=0\\3x-5=0\\3x=5\\x=\frac{5}{3}\\(x=1\frac{2}{3})$

Look at the value of x then find the answer that matches the value of x.

Now for y, substitute x = 5/3 in y = -x-3 (or in 2x-8 if you want.)

$y=-\frac{5}{3} -3\\y=-\frac{5}{3} -\frac{9}{3} \\y=-\frac{14}{3} \\(y=-4\frac{2}{3} )$

So the answer is the second choice.

6 0

2 years ago