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3 years ago

4x+4=2/3 (3x +9) - 18 solve for x

Mathematics

1 answer:

omeli [17]3 years ago

6 0

Answer:

= − 8

Step-by-step explanation:

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Line segment AB has endpoints A(0, 3) and B(2, 2). What is the midpoint of<br> line segment AB?

Anvisha [2.4K]

I think it would be b because if you use the midpt formula it’d turn out to be that ?

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3 years ago

Elizabeth has 1 7/10 as many plants as Rosalie has in her arden. If Elizabeth has 51 plants, how many plants does Rosalie have i

dexar [7]

Question: Elizabeth has 1 7/10 as many plants as Rosalie has in her garden. If Elizabeth has 51 plants, how many plants does Rosalie have in her garden?

Answer: X=30

explanation:

1 7/10 can be rewritten as 1.7

x=amount of plants that Rosalie has

x=1.7/51

x=30

question answered by

(jacemorris04)

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3 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

Fantom [35]

Let t become the time he spent commuting on the first day of his vacation.

It is then calculated as $t + 2$ .

$\to 40\times(t+2) = 60(t) + 20 \\\\\to 40t+80 = 60t + 20 \\\\\to 80-20 = 60t + 40t \\\\\to 60 = 20t \\\\\to t=\frac{60}{20} \\\\\to t=\frac{6}{2} \\\\\to t= 3\\\\$

It traveled $40\times (3 + 2) + 20 = 40\times 5 + 20 = 200+20=220$ miles on its first day of operation.

The car traveled $180\ miles$ on the second day, which was $60 \ miles \times 3$ .

So,

Total mileage= first day traveled + second day traveled $= 220+ 180= 400 \miles$

Learn more:

Total distance traveled: brainly.ph/question/11690847

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3 years ago

5. What would the graph of y= 3/4x -7/8 look like?

garik1379 [7]

A curve is the answer

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2 years ago

Determine the slope of the line that passes through each pair of points.

Soloha48 [4]

$1.)\\\\(5,1) \ \ and \ \ (2,7)\\\\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 7-1}{2-5} = \frac{6}{-3}=-2 \\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=-2 , \ \x_{1}=5, \ \ y_{1}=1 \\ \\y-1 = -2(x-5 ) \\\\y=-2x+10+1 \\ \\y=-2x+11$

$2.)\\\\(5,3)\ \ and \ \ (-2,3)\\\\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 3-3}{-2-5} = \frac{0}{-7}=0\\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=0 , \ \x_{1}=5, \ \ y_{1}=3 \\ \\y-3 = 0\cdot (x-5 ) \\\\y-3=0 \\ \\y=3$

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3 years ago