All categories

3 years ago

It costs 11$ for 15 granola bars.

Mathematics

1 answer:

Jet001 [13]3 years ago

5 0

Answer:

Each granola bar costs $0.73.

Step-by-step explanation:

11/15 = 0.73

You might be interested in

How to solve d - 5 = 7 algebraically

adelina 88 [10]

Answer:

d = 12

Step-by-step explanation:

d - 5= 7

( d - 5 ) + 5 = 7 + 5

d - 5 + 5 = 12

d = 12

6 0

3 years ago

Read 2 more answers

Serena’s average speed during her training run was 8 kilometers per hour over the 2 hours that she ran. What was the total dista

Volgvan

Step-by-step explanation:

so, we just enter the given data into the given formula. and then calculate. it does not get easier than that.

d = 8km/h × 2h = 16km

Serena ran 16km in these 2 hours.

7 0

2 years ago

What is the answer to this question about dividing fractions5 5⁄6 ÷ 3 2⁄4=

Lady_Fox [76]

[~Answer~] (4.):
<em>Hello there! I'm Avery, and I'm here to help you! I mostly believe the answer </em><em>is 1 2/3

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++</em>

[~Answer Explanation~]:

First:

Convert any mixed numbers to fractions.

Reduce fractions where possible.

Then your initial equation becomes:

356÷72

Applying the fractions formula for division,

=35×26×7

=70/42

Simplifying 70/42, the answer is

=1 2/3

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
[~Last Messages~]:

Okay, I really hope my answer is correct.

I am truly sorry if it's wrong :(

Have a great morning, afternoon, or night. <333

[-!AveryIsSomeHowAlive!-]

3 0

1 year ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers

What is 3.06 rounded to the nearest whole number

Gnom [1K]

3.06 rounded to the nearest whole number is 3.
.06 is much closer to 0 than it is to 1, so round down.
3.06 rounded down is 3, so that is your answer.

4 0

3 years ago