Answer: a) 0.0792 b) 0.264
Step-by-step explanation:
Let Event D = Families own a dog .
Event C = families own a cat .
Given : Probability that families own a dog : P(D)=0.36
Probability that families own a dog also own a cat : P(C|D)=0.22
Probability that families own a cat : P(C)= 0.30
a) Formula to find conditional probability :
(1)
Similarly ,

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792
b) Again, using (2)

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264
You would multiply 8m by m and 6 separately. it would be 8m^2 + 48m
Answer:
Step-by-step explanation:
= (x^2 + h^2 - 2xh) + (y^2 + k^2 - 2yk) As, (a-b)^2 = a^2 + b^2 - 2ab
= x^2 + h^2 - 2xh + y^2 + k^2 - 2yk