ANSWER
![(t, \frac{5}{2}t - 3) \: \: where \: t \in \: R](https://tex.z-dn.net/?f=%28t%2C%20%5Cfrac%7B5%7D%7B2%7Dt%20-%203%29%20%5C%3A%20%20%5C%3A%20where%20%5C%3A%20t%20%20%5Cin%20%5C%3A%20R)
EXPLANATION
The given line is
![5x - 2y = 6](https://tex.z-dn.net/?f=5x%20-%202y%20%3D%206)
This is a linear equation in two variables.
There are infinitely many solutions.
Let us solve for y.
![2y = 5x - 6](https://tex.z-dn.net/?f=%202y%20%3D%205x%20-%206)
![\frac{2y}{2} = \frac{5}{2} x - \frac{6}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2y%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B5%7D%7B2%7D%20x%20-%20%20%5Cfrac%7B6%7D%7B3%7D%20)
![y = \frac{5}{2}x - 3](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B5%7D%7B2%7Dx%20-%203)
Let
![x = t](https://tex.z-dn.net/?f=x%20%3D%20t)
Then
![y =\frac{5}{2}t - 3](https://tex.z-dn.net/?f=y%20%3D%5Cfrac%7B5%7D%7B2%7Dt%20-%203)
The group of ordered pairs which are on the given line are represented by:
![(t, \frac{5}{2}t - 3)](https://tex.z-dn.net/?f=%28t%2C%20%5Cfrac%7B5%7D%7B2%7Dt%20-%203%29)
Where t is real number.
The length of room = 10 ft
the width = 14 ft
the height = 12 ft
there are 4 walls and the floor
one wall has area = 10*12=120 ft^2
4 walls has area = 4*120=480 ft^2
the floor has area = 10*14=140 ft^2
total area of walls and floor = 480+140= 620 ft^2
- so bc. we know that each tile is 1 foot long and 1 foot wide so what mean an area of 1 ft^2 and the total area equal 620 ft^2 so this mean that Jamie will need 620 tiles
x - 6 =
+ 6
First, Evaluate the power:
<u><em>
</em></u> x - 6 = <u><em>
</em></u> + 6
729x - 6 = 19683 + x
Next, move the variable to the left side and change it's sign, then the constant to the right side and change its sign:
729x - <u><em>6 </em></u>= 19683 + <u><em>x</em></u>
Next, collect like terms and add the numbers:
<u><em>729x - x</em></u> = <u><em>19683 + 6</em></u>
728x = 19689
Finally divide both sides of the equation by 728 (any expression divided by itself equals 1):
x = 19689 / 728
x = 27 ![\frac{33}{728}](https://tex.z-dn.net/?f=%5Cfrac%7B33%7D%7B728%7D)
<span>A circle is 360° all the way around; therefore, if you divide an arc’s degree measure by 360°, you find the fraction of the circle’s circumference that the arc makes up. Then, if you multiply the length all the way around the circle (the circle’s circumference) by that fraction, you get the length along the arc.</span>