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STALIN [3.7K]
2 years ago
12

B)

Mathematics
1 answer:
ollegr [7]2 years ago
5 0

Answer:

P + Q = 1

Step-by-step explanation:

Given: \frac{1+\sqrt{3} }{1-\sqrt{3} }  = P - \sqrt{Q}

This is a question on surd, so we need to rationalize the denominator to have;

\frac{1+\sqrt{3} }{1-\sqrt{3} }  * \frac{1+\sqrt{3} }{1+\sqrt{3} } = \frac{1+\sqrt{3}+\sqrt{3}  + 3}{1+\sqrt{3}-\sqrt{3} -3 }

   = \frac{4+ 2\sqrt{3} }{1-3}

   = \frac{4+2\sqrt{3} }{-2}

   = -2 - \sqrt{3}

Thus,

-2 - \sqrt{3} = P - \sqrt{Q}

⇒ P = -2 and Q = 3

Therefore, the value of P + Q = -2 + 3

                                                 = 1

Thus,

P + Q = 1

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\bf \textit{distance between 2 points}\\ \quad \\
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\\\\\\
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so, what's the equation of a circle with center at -3, -1 and a radius of 5?

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
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