Answer:
Mean of sampling distribution = 5.10 alcoholic drinks per week
Standard deviation of the sampling distribution = 0.11
Step-by-step explanation:
We are given the following in the question:
Mean, μ = 5.10 alcoholic drinks per week
Standard Deviation, σ = 1.3401
Sample size, n = 150
a) Mean of sampling distribution
The best approximator for the mean of the sampling distribution is the population mean itself.
Thus, we can write:
b) Standard deviation of the sampling distribution
Answer:
.
Step-by-step explanation:
Probability that the car encounters a green light on the first day: .
To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be
.
To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be .
To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day.
The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: .