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Mariana [72]
3 years ago
10

Find the sum. 637,391 + 372,088 *

Mathematics
1 answer:
ivanzaharov [21]3 years ago
5 0

Answer:

1,009,479

Step-by-step explanation:

dude there 8a some thing called as a CALCULATOR

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Write x2 y2 – 18x 8y 5 = 0 in standard form. group terms and move the constant to the other side of the equation. x2 – 18x y2 8y
Mashutka [201]

The equation of the circle x² + y² – 18x + 8y + 5 = 0 can be written as in the standard form is (x – 9)² + (y + 4)² = 92

<h3>What is a circle?</h3>

It is a locus of a point drawn equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

The equation of the circle is given below.

x² + y² – 18x + 8y + 5 = 0

Add and subtract 97, then we have

x² – 18x + y² + 8y + 97 – 97 + 5 = 0

x² – 18x + 81 + y² + 8y + 16 – 92 = 0

                        (x – 9)² + (y + 4)² = 92

More about the circle link is given below.

brainly.com/question/11833983

6 0
3 years ago
3x -2 &gt; -11<br><br> (The &gt; has an underscore under it)
user100 [1]

3x-2\geq-11

3x\geq-9

x\geq-3

x\in[-3, \infty)

Hope this helps.

7 0
3 years ago
What is the area of a triangle with vertices at (-4,1), (-7,5) and (0,1)
Arlecino [84]

Answer:

62.1467 square units (correct to four decimal places)

Step-by-step explanation:

Let's say the triangle is;

A(-7,5)

B(-4,1)

C(0,1)

Let's say also that AB = a , BC = b  and AC = c

By measurement BC = 4 units , AB = 5 units (applying Pythagorean theorem) and AC = 8.1 units (correct to one decimal place) also through Pythagorean theorem.

Area of this triangle = \sqrt{p(p-a)(p-b)(p-c)} , where p is half the perimeter of the triangle

p = \frac{1}{2}(4 + 8 + 8.1) = 8.55 units

Area = \sqrt{8.55(8.55-5)(8.55-4)(8.55-8.1)} = 62.1467 square units (correct to four decimal places)

4 0
3 years ago
Which table describes the behavior of the graph of f(x) = 2x³ - 26x - 24?
Anna71 [15]
After you have plotted the graph of the polynomial, the x-intercepts of the given polynomial will be:
(-3,0),(-1,0) and (4,0)
therefore the interval will be:
(-∞,-3)-below, (-3,-1)-above,(-1,4)-below,(4,∞)-above
The answer is ]


4 0
3 years ago
Read 2 more answers
2X(X+y) + 2y(3X-y)<br> Please help me
tankabanditka [31]

Answer:

2x^2 + 8xy - 2y^2

Step-by-step explanation:

2X(X+y) + 2y(3X-y)

2x^2 + 2xy + 6yx - 2y^2

2x^2 + 8xy - 2y^2

7 0
3 years ago
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