Answer:
<u>H</u><u>e</u><u>y</u><u> </u><u>M</u><u>a</u><u>t</u><u>e</u><u>!</u><u> </u><u>H</u><u>e</u><u>r</u><u>e</u><u>'</u><u>s</u><u> </u><u>y</u><u>o</u><u>u</u><u>r</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>.</u>
Step-by-step explanation:
<em><u>One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25</u></em>
<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32</u></em>
<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35</u></em>
<em><u>Total ingradiants for one packet of biscuits =</u></em>
<em><u>Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625</u></em>
<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =</u></em>
<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32</u></em>
Hope it helped you!
For this specific problem, x
rounded to the nearest meter is 4. I am hoping that this answer has
satisfied your query about and it will be able to help you, and if you’d like,
feel free to ask another question.
Answer:3
Step-by-step explanation:
Answer:
0.83
Step-by-step explanation:
Part A: 5 out 25 lobsters have dangerous levels of mercury
Part B: the 95% confidence interval is given by (4.45, 5.65)
since everything is given all I had to do is find the critical value which can be found from the resource packet = 2.064
Using the formula we find 5.05+-2.064*1.45/5 = ( 4.45,5.65)
For this case, we have 95% of confidence that the true mean for the average number of lobsters with dangerous levels of mercury is between 4.45,5.65