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3 years ago

The results of 11 students in a test are:4,19,7,18,15,9,17,14,10,13,11. what is the median.

Mathematics

2 answers:

Yanka [14]3 years ago

7 0

Answer do 4 *11

Step-by-step explanation:

alexdok [17]3 years ago

7 0

The median score is the middle number . BUT you have to rewrite the numbers from least to greatest THEN cross out first number then last number and keep repeating until you are left with one number in the middle . If you are left with two numbers in the middle then add them and divide by two to get your middle number . So let’s do it :
4, 7, 9, 10, 11, 13, 14, 15, 17, 18, 19
Your answer is 13

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What is the percent / degree of X ?

tia_tia [17]

Answer: 65

Step-by-step explanation:

All those angles added up have to equal 360 degrees.

The little square on the angle to the left of x means that it's a right angle, or 90 degrees.

360

- 180

= 180 <--- this is the bottom half,

180

- 90 <--- the right angle on the left

= 90

-25

= 65 <--- that's x

8 0

2 years ago

The rule is applied to ΔFGH to produce ΔF"G"H". What are the

ss7ja [257]

Answer:

A - (4, –1.5)

Step-by-step explanation: Hope it helps :D

7 0

3 years ago

Read 2 more answers

Helps pls :-/<br> number 12<br> any help is greatly appreciated!

Alexandra [31]

X = 5, that’s the answer to question 12

6 0

3 years ago

Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

4 0

2 years ago

Evaluate the expression 14c + 28 - 12d for the give value c=4 and d=5

expeople1 [14]

(Use order of operations(PEMDAS))

14(4)+28-12(5)
56+28-60
84-60
24

solution=24

4 0

3 years ago

The results of 11 students in a test are:4,19,7,18,15,9,17,14,10,13,11. what is the median.​

The results of 11 students in a test are:4,19,7,18,15,9,17,14,10,13,11. what is the median.