Answer:
1) (x + 3)(3x + 2)
2) x= +/-root6 - 1 by 5
Step-by-step explanation:
3x^2 + 11x + 6 = 0 (mid-term break)
using mid-term break
3x^2 + 9x + 2x + 6 = 0
factor out 3x from first pair and +2 from the second pair
3x(x + 3) + 2(x + 3)
factor out x+3
(x + 3)(3x + 2)
5x^2 + 2x = 1 (completing squares)
rearrange the equation
5x^2 + 2x - 1 = 0
divide both sides by 5 to cancel out the 5 of first term
5x^2/5 + 2x/5 - 1/5 = 0/5
x^2 + 2x/5 - 1/5 = 0
rearranging the equation to gain a+b=c form
x^2 + 2x/5 = 1/5
adding (1/5)^2 on both sides
x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2
(x + 1/5)^2 = 1/5 + 1/25
(x + 1/5)^2 = 5 + 1 by 25
(x + 1/5)^2 = 6/25
taking square root on both sides
root(x + 1/5)^2 = +/- root(6/25)
x + 1/5 = +/- root6 /5
shifting 1/5 on the other side
x = +/- root6 /5 - 1/5
x = +/- root6 - 1 by 5
x = + root6 - 1 by 5 or x= - root6 - 1 by 5
Answer:
x = 1178 games
Step-by-step explanation:
Let the number of games = x
Let the total cost = Tc
Let the total revenue = Tr
Given the following data;
Investment = $10,000
Cost of each game = $1.50
Selling cost = $9.99
Total cost, Tc = (Cost of each game * Number of games) + Investment
Tc = 1.50x + 10000
Total revenue, Tr = Selling cost * Number of games
Tr = 9.99x
Breakeven point is when total cost is equal to total revenue;
Tc = Tr
x = 1177.86 ≈ 1178 games.
<em>Therefore, the number of games that must be sold before the business breaks even is 1178 games. </em>
You first have to convert the 5 tons to pounds.
Once you have done that step you simply add.
QP is the bisector so QPM is half NPM or
