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3 years ago

ABC is an isosceles with AB=AC=6cm. If BC=7cm,find angle C.

Mathematics

1 answer:

Vsevolod [243]3 years ago

7 0

Answer:

54.314 °

Step-by-step explanation:

It is given that in triangle ABC, AB = AC = 6m. So, it is an isosceles triangle

Now, it is also given that BC = 7 cm.

We have to find the value of angle C.

If we draw a perpendicular on BC from point A, then it will bisect BC at D i.e. AD is a perpendicular bisector of BC.

Now, the triangle ADC is a right triangle in which, the base DC =7/2 =3.5 cm and hypotenuse AC = 6m (Given) and angle ADC= 90°.

Therefore, Cos∠C = DC/AC =3.5/6.

⇒ ∠C =Cos⁻¹ (3.5/6) =54.314 ° (Answer)

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4 years ago

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3 years ago

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3 years ago

Can someone help me

kolbaska11 [484]

m < 1 = 130°

m < 1 = 130°m < 2 = 50°

We know this is a linear pair, therefore the two angles must add up to 180°

$(m < 1 )+ (m < 2 )= 180$

$5x + x + 24 = 180$

Combine like terms

$6x + 24 = 180$

Isolate the variable

$6x = 156$

$x = 26$

Plug in 26 for x in both of the individual angle equations.

$m < 1 = 5x$

$= 5(26)$

$= 130$

$m < 2 = x - 24$

$= (26) + 24$

$= 50$

A good way to check if we did this correctly, is to add up the two angles. Because 180 + 50 = 180, we did this correctly.

I hope this helped. Let me know if you have any questions!

6 0

3 years ago

ABC is an isosceles with AB=AC=6cm. If BC=7cm,find angle C.​

ABC is an isosceles with AB=AC=6cm. If BC=7cm,find angle C.