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hjlf
3 years ago
10

What is the random movement and mixing of particles?

Chemistry
1 answer:
kherson [118]3 years ago
5 0

Answer:

diffusion

Explanation:

Diffusion can be defined as the net movement of particles from a high concentration to a low concentration. This sounds like the most plausible word in this case.

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A solution that is 0.16 M in HCHO2 and 0.13 M in NaCHO2. Express your answer using two decimal places.
jolli1 [7]
Lol ok so i really don’t know sorry
4 0
4 years ago
At an atmospheric pressure of 870 mm hg of 21% oxygen, the partial pressure of oxygen is
BARSIC [14]
Atmosphere is made of a mixture of gases. Each individual gas exerts a pressure known as the partial pressure.
The sum of the partial pressures exerted by each gas in the mixture is equal to the total pressure exerted by the mixture of gases as a whole.
The partial pressure depends on the composition of the gas in the mixture.
In this case the total pressure - 870 mmHg
21% of atmosphere is oxygen
partial pressure of Oxygen = 870 mmHg x 21%  = 182.7 mmHg
7 0
4 years ago
2KCIO3 ----------&gt; 2KCI + 302<br> How many moles of KCIO3 are needed to make 3.5 moles of KCL?
lyudmila [28]

Answer:

3.5 mol KClO3

Explanation:

Given 3.50 moles of KCl as the target amount in the problem, used the coefficient of the balanced chemical reaction involved to determine the number of moles of potassium perchlorate needed.

x mole of  KClO3  = 3.5 mol  KCl x [(2 mol KCl)/ (2 mol KClO3)] = 3.5 mol KClO3

x mole of  KClO3 = 3.5 mol KClO3

3 0
3 years ago
What term describes a substance that does the dissolving
NARA [144]
 A <span>substance that does the dissolving is called a </span>solute. 
5 0
3 years ago
A container of carbon dioxide has a volume of 260 cm at a temperature of 22.0°C. If the
Oxana [17]

Answer:

V₂ =279.4 cm³

Explanation:

Given data:

Initial volume = 260 cm³

Initial temperature = 22.0°C

Final temperature = 44.0°C

Final volume = ?

Solution;

22.0°C (22+ 273 = 295k)

44.0°C(44+273 = 317k)

Formula:

According to Charles's law

V₁/T₁ = V₂/T₂

Now we will put the values in formula:

V₂ = V₁×T₂ / T₁

V₂ = 260 cm³ × 317k / 295k

V₂ = 82420 cm³. k  / 295k

V₂ =279.4 cm³

3 0
4 years ago
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