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Harman [31]
3 years ago
10

Which greenhouse gas typically exists in both the stratosphere and the troposphere?

Chemistry
2 answers:
Arturiano [62]3 years ago
5 0
The answer should be ozone
crimeas [40]3 years ago
4 0
The ozone layer is a greenhouse gas that is in both the stratosphere and troposphere.
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Calculate the moles and grams of solute in each solution. D. 2.0 L of 0.30M Na2SO4. I already have A, B, and C. Thanks!
e-lub [12.9K]
Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol


Find the molar mass
2Na = 23 * 2 = 46 grams
1S   = 32 * 1 = 32 grams
O4   = 16 * 4 = 64 grams
Total =            142 grams / mol

Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???

given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams. 

85.2 are in a 2 L solution that has a concentration of 0.6 mol/L


4 0
3 years ago
Read 2 more answers
When does the dipole arrow point to Atom A? (Use electronegativity in your explanation)
Marrrta [24]

Answer:

Dipole, less electronegativity,  higher electronegativity

8 0
3 years ago
Composition of matter which depends on temperature.
Arte-miy333 [17]

Phase of matter

Explanation:

The phase of matter strictly is a function of its temperature. Matter exists in different phases at different temperatures.

  • Matter is anything that has weight and occupies space.
  • There are three states of matter:
  1. Solid
  2. Liquid
  3. Gas

These phases of matter depends on temperature.

For example;

  • Water exists as gases above boiling point
  • Water is also solid at freezing point.
  • Between the freezing and boiling point, water is a liquid.

Learn more:

Chemistry brainly.com/question/8839455

#learnwithBrainly

7 0
3 years ago
How many milliliters of 0.258M NaOH are required to completely neutralize 2.00 g of acetic acid HC2H3O2?
madam [21]

Answer:

0.129 L = 129.0 mL.

Explanation:

  • NaOH neutralizes acetic acid (CH₃COOH) according to the balanced reaction:

<em>NaOH + CH₃COOH → CH₃COONa + H₂O.  </em>

  • According to the balanced equation: 1.0 mole of NaOH will neutralize 1.0 mole of CH₃COOH.  

<em>no. of moles of CH₃COOH = mass/molar mass </em>= (2.0 g)/(60 g/mol) = <em>0.033 mole.  </em>

<em> </em>

  • For NaOH:

no. of moles = (0.258 mol/L)(V)

  • At neutralization: no. of moles of NaOH = no. of moles of CH₃COOH  

∴ (0.258 mol/L)(V) = 0.033 mole

<em>∴ The volume of NaOH</em> =  (0.033 mole)/(0.258 mol/L) = <em>0.129 L = 129.0 mL.</em>

8 0
4 years ago
28.
allochka39001 [22]

Answer: I believe that B) require target cell receptors to illicit a target cell response, is the right answer.

Explanation:

6 0
3 years ago
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