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baherus [9]
3 years ago
9

How much heat is lost or gained by the calorimeter

Chemistry
1 answer:
Maslowich3 years ago
5 0

Answer:

1.113 kJ or 1,113 J.

Explanation:

I hope this helps :)

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Which of the following distinguishes a nuclear reaction from a chemical reaction? a.It involves atoms.
Leokris [45]
The answer is:
A. <span>It involves atoms. </span>
8 0
4 years ago
Br NaOCH2CH3 + CH3CH-OH + NaBr CH3 CH3 a. Identify the mechanism of the reaction. b. Suggest steps for the mechanism of this rea
Ulleksa [173]

Answer:

a) The mechanism of the reaction is the Elimination Bimolecular or E2.

b) Steps for the mechanism of this reaction is given as follows,

c) Reaction rate = K[Organic compound][NaoCH_{2} CH_{3}].  

Explanation:

a) The mechanism of the reaction is the Elimination Bimolecular or E2.

c) This is an E2 reaction, so it depends on the concentration of both substrate and reactant. If we increase the concentration of NaoCH_{2} CH_{3}, the reaction rate will be increased.

Reaction rate = K[Organic compound][NaoCH_{2} CH_{3}].  

b) Steps for the mechanism of this reaction is given as follows,

3 0
3 years ago
1. What are the two sources of thermal energy in Earth's interior?
mamaluj [8]

Answer: What is one source of thermal energy in the interior of the Earth?

Explanation:

8 0
4 years ago
A 150 mL of oxygen gas is collected over water at 20 °C and 758 torr. What volume will the same sample of oxygen occupy at STP w
Stella [2.4K]

Answer:

The volume would be; 136.17 ml

Explanation:

Volume V1 = 150 mL

Temperature T1 = 20°C + 273 = 293 K

Pressure  P1 = 758 - 17.54 = 740.46 torr

At STP;

Volume V2 = ?

Pressure P2 = 760 torr

Temperature T2 = 273 K

Using the general gas equation;

P1V1 / T1   = P2V2 / T2

Making V2 subject of formulae;

V2 = P1V1T2 / T1P2

Inserting the values we have;

V2 = 740.46 * 150 * 273  /  293 * 760

V2 = 136.17 ml

3 0
3 years ago
HELP PLZ!CHEMISTRY.WILL GIVE BRAINLIEST!!!!
Andrej [43]

1. 12 L = 12 dm³

2. 3.18 g

<h3>Further explanation</h3>

Given

1. Reaction

K₂CO₃+2HNO₃⇒ 2KNO₃+H₂O+CO₂

69 g K₂CO₃

2. 0.03 mol/L Na₂CO₃

Required

1. volume of CO₂

2. mass Na₂CO₃

Solution

1. mol K₂CO₃(MW=138 g/mol) :

= 69 : 138

= 0.5

mol ratio of K₂CO₃ : CO₂ = 1 : 1, so mol CO₂ = 0.5

Assume at RTP(25 C, 1 atm) 1 mol gas = 24 L, so volume CO₂ :

= 0.5 x 24 L

= 12 L

2. M Na₂CO₃ = 0.03 M

Volume = 1 L

mol Na₂CO₃ :

= M x V

= 0.03 x 1

= 0.03 moles

Mass Na₂CO₃(MW=106 g/mol) :

= mol x MW

= 0.03 x 106

= 3.18 g

3 0
3 years ago
Read 2 more answers
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