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3 years ago

If ACD~ABE find the value of x

Mathematics

1 answer:

bearhunter [10]3 years ago

7 0

Step-by-step explanation:

I think it is a good day and the answer is 3

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What is the range of the graph

vfiekz [6]

The range of a graph is the set of possible output values, which are shown on the y-axis

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3 years ago

Factor pairs for each number 49

Aleks04 [339]

1 x 49
7 x 7
i don't think there is anymore factors f0r 49

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4 years ago

Read 2 more answers

Which set of points on the graph represents equivalent ratios?

swat32

Answer:

points A C and d <3

Step-by-step explanation:

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3 years ago

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The net weight in pounds of a packaged chemical herbicide is uniform for 49.62 < x < 50.04 pounds.

k0ka [10]

Answer:

a) $E(X)=\frac{50.64+49.62}{2}=50.13 pounds$

b) $Var(X)= \frac{(b-a)^2}{12} =\frac{(50.04-49.62)^2}{12}=0.0147$

c) $P(X$

But we see that the distribution is defined ust between 49.62 and 50.04

And in order to find this we can use the CDF (Cumulative distribution function) given by:

$F(X) =\frac{x-a}{b-a}$

And if we replace we got:

$P(X$

And makes sense since all the values are between 49.62 and 50.04

Step-by-step explanation:

For this case we define the random variable X ="net weigth in pounds of a packaged chemical herbicide" and the distribution for X is given by:

$X \sim U(a= 49.62, b=50.04)$

Part a

For the uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

$E(X)=\frac{50.64+49.62}{2}=50.13 pounds$

Part b

The variance for an uniform distribution is given by:

$Var(X)= \frac{(b-a)^2}{12}$

And if we replace we got:

$Var(X)= \frac{(b-a)^2}{12} =\frac{(50.04-49.62)^2}{12}=0.0147$

Part c

For this case we want to find this probability:

$P(X$

But we see that the distribution is defined ust between 49.62 and 50.04

And in order to find this we can use the CDF (Cumulative distribution function) given by:

$F(X) =\frac{x-a}{b-a}$

And if we replace we got:

$P(X$

And makes sense since all the values are between 49.62 and 50.04

6 0

4 years ago

To qualify for a scholarship, a student must score at least 90% on a written test. The test is 64 questions. Using this metric,

Ket [755]

Answer:

6 questions

Step-by-step explanation:

First, you divide the total score of 100 by the 64 questions to get 1.5625 points per question. Next, you divide the lowest score to qualify of 90 by the 1.5625 to get 57.6 questions correct to qualify. Then, you round 57.6 questions correct up to 58 questions correct because a fraction of a question correct doesn't make sense. Finally, you subtract the total number of questions (64) by the required correct answers (58) to get 6 questions you can miss to still qualify for the scholarship.

6 0

3 years ago