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In-s [12.5K]
3 years ago
7

How many solutions are there to the equation below 6x+15=6(x+3)

Mathematics
2 answers:
Shalnov [3]3 years ago
8 0

Answer:

The equation has Zero solution.

Step-by-step explanation:

Consider the provided equation.

6x+15=6(x+3)

Apply the distributive property: a(b+c)=ab+ac

6x+15=6x+18

Now isolate the variables by subtracting 6 from both the sides.

6x+15-6x=6x+18-6x

15=18

Which is not true.

Hence, the equation has no solution or the equation has Zero solution.

cupoosta [38]3 years ago
7 0
6x + 15 = 6 (x + 3)

6x + 15 = 6x + 18

6x = 6x + 3

0 = 3


So, there are no solutions to this equation.
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2.\\a)\ 5x-y+3=0\ \ \ |add\ y\ to\ both\ sides\\\\\boxed{y=5x+3}\\\\d)\ 7x+2y-3=0\ \ \ |subtract\ 7x\ from\ both\ sides\\\\2y-3=-7x\ \ \ |add\ 3\ to\ both\ sides\\\\2y=-7x+3\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{y=-3.5x+1.5}


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6 0
3 years ago
In a class of 26 students, 15 of them like maths, 13 of them like English and 9 of them don't like Maths or English. Find the pr
galben [10]

Answer: 0 0769

Step-by-step explanation:

Let x be the number of students that offer both subjects

15 - x + x + 13 - x + 9 = 26

-x + 37 = 26

-x = -11

x = 11

Number of student that offer english but not math = 13 - 11 = 2

The probability of english but not math = 2/26 = 0.0769

7 0
3 years ago
There are 3 first grade children, 5 second grade children, and 7 third grade children in a room. When choosing two children, wha
ycow [4]

Answer:

0.3571 or 35.14%

Step-by-step explanation:

There are 15 children in total in the class at first. Of those children, 5 are second graders and 10 are not.

If the first chosen children was not a second grader, there are 5 second graders among the 14 children left. The probability of selecting a second grade child is:

P = \frac{5}{14}\\P=0.3571\\P=35.71\%

The probability is 0.3571 or 35.14%.

4 0
3 years ago
Read 2 more answers
For which equation does it make the most sense to solve by completing the square?
ludmilkaskok [199]
The last equation is the most suitable one to be solved by completing the square .
5 0
3 years ago
Read 2 more answers
5470
nadya68 [22]

Answer:  1144

Step-by-step explanation:

Given: Machine A makes 7 parts every 10 minutes.

i.e. it makes \dfrac{7}{10} parts in 1 minute.

Machine B makes 16 parts every 15 minutes.

i.e. it makes \dfrac{16}{15} parts in 1 minute.

On Monday,

machine A makes parts for 12 hours(720 minutes).    [1 hour = 60  minutes, 12 hours = 12 x 6 = 720 minutes]

i.e. Total parts made = \dfrac{7}{10}\times720

i.e. Total parts made = 504

machine B makes parts for 10 hours(=60x 10=600 minutes)

i.e. Total parts made = \dfrac{16}{15}\times600

i.e. Total parts made = 640

Total parts made by both machines = 504+640 =1144

Hence, the total number of parts made by the two machines on Monday=1144.

7 0
3 years ago
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