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3 years ago

Please help!!! It's about the types of quantities if they are proportional or not if there is a constant number.

Mathematics

1 answer:

alekssr [168]3 years ago

7 0

1. Yes, because y=kx. “Y” is equal to 4 × “x”, on every problem. y=4x
2. No, because on the first set of numbers 3 and 15 the equation is Y=5x. Then on the second set of numbers 4 and 17 the equation is Y=4.25x.
3. Yes, because Y=1.5x.

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What is the cotangent of Angle Q !! look at the pic for answer choices and the triangle

vfiekz [6]

√29/2 since cotangent deals the reciprocal of tangent and cotangent value is adjacent side/opposite side

8 0

2 years ago

Solve for x and state the measure of the angles with an x in them

Arada [10]

Answer:

x = 83

Step-by-step explanation:

The sum of the angles of a quadrilateral is 360

75+x+97+105 = 360

Combine like terms

x+277=360

Subtract 277 from each side

x+277-277=360-277

x = 83

5 0

2 years ago

Read 2 more answers

Please help find and plot the reflection of this. I will mark brainliest

lubasha [3.4K]

Answer:

Look below for coordinates

Step-by-step explanation:

A: -2, 3 to A': -2, -3

B: 5, -2 to B': 5, 2

C: -5, 1 to C': -5, -1

Reflect over x-axis: (x, -y) and Reflect over y-axis: (-x, y)

7 0

2 years ago

What's 2 meters to 76 centimeters in simplest form

Komok [63]

Answer:

I am not really getting your question. Could you comment on this answer?

1 meter = 100 centimeters

Ratio:

2 m : 76 cm

200 cm : 76 cm

2 m : 0.76 m

6 0

2 years ago

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is:

$74.2-(1.8331)\frac{5.3083}{\sqrt{10} }$ ≤ μ ≤ $74.2+(1.8331)\frac{5.3083}{\sqrt{10} }$

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0

2 years ago