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Fynjy0 [20]
3 years ago
13

Please help!!! It's about the types of quantities if they are proportional or not if there is a constant number.

Mathematics
1 answer:
alekssr [168]3 years ago
7 0
1. Yes, because y=kx. “Y” is equal to 4 × “x”, on every problem. y=4x
2. No, because on the first set of numbers 3 and 15 the equation is Y=5x. Then on the second set of numbers 4 and 17 the equation is Y=4.25x.
3. Yes, because Y=1.5x.
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PLEASE HELP ASAP 9TH GRADE MATH AND I NEED HELP, 15 POINTS AND BRAINLIST HELPPPP
Sunny_sXe [5.5K]

Answer:

x = 40°

Step-by-step explanation:

Given that ∠SRT ≅ ∠STR

Then ∠STR = 20

∠STR  and ∠STU are what you call supplementary angles. This means that the sum of their measurements is equal to 180° because they form a straight line.

So if:

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Now we solve for x:

4x + 20 = 180\\\\Subtract\;20\;from\;both\;sides\;of\;the\;equation\\\\4x + 20 - 20 = 180 - 20\\4x = 160\\\\Divide\;both\;sides\;of\;the\;equation\;by\;4\\\\\dfrac{4x}{4}=\dfrac{160}{4}\\\\x = 40

x = 40°

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3 years ago
Which of the following is the smallest element in the set of natural numbers?
fredd [130]

Answer:

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2 years ago
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Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
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