Answer:
16
Step-by-step explanation:
look at picture
Answer:
All of the above
Step-by-step explanation:
dy/dt = y/3 (18 − y)
0 = y/3 (18 − y)
y = 0 or 18
d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)
d²y/dt² = dy/dt (-y/3 + 6 − y/3)
d²y/dt² = dy/dt (6 − 2y/3)
d²y/dt² = y/3 (18 − y) (6 − 2y/3)
0 = y/3 (18 − y) (6 − 2y/3)
y = 0, 9, 18
y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.
y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.
<u><em>Answer:</em></u>
Number of child tickets sold that day = 25 tickets
<u><em>Explanation:</em></u>
Assume that the number of the adult ticket is x and that the number of the child ticket is y.
<u>We are given that:</u>
1- four times as many adult tickets as child tickets were sold. <u>This means that:</u>
adult tickets = 4 * child tickets
x = 4y ....................> equation I
2- Child ticket costs $5.5, adult ticket costs $9.1 and total sales was $1047.5.
<u>This means that:</u>
x(9.1) + y(5.5) = 1047.5
9.1x + 5.5y = 1047.5 ..................> equation II
<u>Substitute with equation II in equation I and solve for y as follows:</u>
9.1x + 5.5y = 1047.5
9.1(4y) + 5.5y = 1047.5
36.4y + 5.5y = 1047.5
41.9y = 1047.5
y = 25
<u>Based on the above calculations:</u>
number of child tickets = y = 25 tickets
number of adult tickets = x = 4y = 4(25) = 100 tickets
Hope this helps :)
A counterexample is an example that disproves a conclusion. For this problem all you have to do is make a list of numbers that are less than zero. Your counterexample could be something like: -1, -1.5, -2, -2.5, -3, -3.5
Only 33% of the students bought tickets.
There you go