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ad-work [718]
3 years ago
5

What type of polygon is pictured here

Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0

Answer:

irregular heptagon

Step-by-step explanation:

You might be interested in
Which steps should be followed to write an equivalent ratio to find 2% of 6700? Write 2% as the ratio StartFraction 200 Over 100
Andrej [43]

Answer:

Step-by-step explanation:

To evaluate the expression 2% 0f 6700, we can follow the steps;

2% = 2/100

6700 = 67(100)

2% of 6700 = 2/100 * 67(100)

The 10 at the numerator will cancel out that at the denominator

2/100 * 67(100) = 2(67)

2(67) = 134

5 0
3 years ago
I need help with this plz.
valina [46]

Answer:

what do u need help with?

Step-by-step explanation:

4 0
3 years ago
Solve the formula A=1/2h(a+b)
lapo4ka [179]

Answer:

Step-by-step explanation:

3 0
2 years ago
An office building loses a third of its heat between sundown and midnight and an additional half of the original amount of heat
Mekhanik [1.2K]

Answer:

\dfrac{1}{16}

Step-by-step explanation:

Proportion of Heat Loss Between sundown and midnight=\dfrac{1}{3}

Proportion of Heat Loss between midnight and 4 AM  =\dfrac{1}{2}

Proportion of Total Heat Already Lost =\dfrac{1}{3}+\dfrac{1}{2} =\dfrac{5}{6}

Proportion of Remaining Heat =1-\dfrac{5}{6}=\dfrac{1}{6}

Between 4 AM and 5 AM, five-eighths of the remaining heat is lost.

Proportion of Heat Loss between 4 AM and 5 AM= \dfrac{5}{8}$ X \dfrac{1}{6} = \dfrac{5}{48}

Therefore, Proportion of Remaining Heat Left =\dfrac{1}{6}- \dfrac{5}{48}=\dfrac{1}{16}

We therefore say that:

\dfrac{1}{16}$ of the total heat loss occurs between 5 AM and sunrise.

6 0
3 years ago
Although still a sophomore at college, John O'Hagan's son Billy-Sean has already created several commercial video games and is c
Scilla [17]

Answer:

<em>27 feet for the south wall and 18 feet for the east/west walls</em>

Maximum area= 486\ ft^2

Step-by-step explanation:

<u>Optimization</u>

This is a simple case where an objective function must be minimized or maximized, given some restrictions coming in the form of equations.

The first derivative method will be used to find the values of the parameters that control the objective function and the maximum value of that function.

The office space for Billy-Sean will have the form of a rectangle of dimensions x and y, being x the number of feet for the south wall and y the number of feet for the west wall. The total cost of the space is

C=8x+12y

The budget to build the office space is $432, thus

8x+12y=432

Solving for y

\displaystyle y=\frac{432-8x}{12}

The area of the office space is

A=xy

Replacing the value found above

\displaystyle A=x\cdot \frac{432-8x}{12}

Operating

\displaystyle A= \frac{432x-8x^2}{12}

This is the objective function and must be maximized. Taking its first derivative and equating to 0:

\displaystyle A'= \frac{432-16x}{12}=0

Operating

432-16x=0

Solving

x=432/16=27

x=27\ feet

Calculating y

\displaystyle y=\frac{432-8\cdot 27}{12}

y=18\ feet

Compute the second derivative to ensure it's a maximum

\displaystyle A'= \frac{-16x}{12}

Since it's negative for x positive, the values found are a maximum for the area of the office space, which area is

A=xy=27\ ft\cdot 18\ ft\\\\\boxed{A=486\ ft^2}

5 0
3 years ago
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