Question

A cyclist at a grocery store, 180m from his home decides to go to the post office which is 510m from his home in the same direction. He takes 45 seconds to make the trip. He then returns home, taking a further 60 seconds.
a. What was his total displacement?
b. What was his average velocity in going from the grocery store to the post office?
c. How much was his average speed in making the entire trip

Answer 1

A) -180m
b) 510-180=+330m
+330/45=7.333m/s
c) total distance = 840m
average speed = 840/105
= 8m/s