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3 years ago

Witch number is a factor of 8 but not a multiple of 4

Mathematics

2 answers:

Korvikt [17]3 years ago

8 0

2 is a factor of 8 and 4 however it is not a multiple of either so the answer is 2

vova2212 [387]3 years ago

5 0

The factors of 8 are 1, 2, 4, and 8.
The first few multiples of 4 are 4, 8, 12, 16, and 20.

The factors of 8 that are multiples of 4 are 4, and 8.
Therefore, the factors of 8 that are not multiples of 4 are 1 and 2.

Hope this helps! :)

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Show work explain with formulas.

Sedaia [141]

Answer:

$\large\boxed{1.\ a_{44}=481,\ \sum\limits_{n=1}^\infty(11n-3),\ \text{the sum not exist}}$

$\large\boxed{3.\ \sum\limits_{n=1}^{47}(9n+16)=10,904}$

$\large\boxed{4.\ \sum\limits_{n=1}^\infty\bigg(6(2^n)\bigg),\ \text{the sum not exist}}$

Step-by-step explanation:

$1.\\8+19+30+41+...\\\\19-8=11\\30-19=11\\41-30=11\\\\\text{It's an arithmetic series.}\ a_1=8,\ d=11.\\\\\text{The formula for the n-th term of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\\text{Substitute:}\\\\a_n=8+(n-1)(11)\qquad\text{use the distributive property}\ a(b-c)=ab-ac\\a_n=8+11n-11\\\boxed{a_n=11n-3}\\\\\text{Calculate the 44th term. Put n = 44 to the formula:}\\\\a_{44}=(11)(44)-3=484-3=481$

$\text{The summation notation:}\\\\\sum\limits_{n=1}^\infty(11n-3)\\\\\text{The sum not exist, because}\ d>1,\ \text{therefore}\ 11n-3\rightarrow\infty.$

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$3.\\25+34+43+52+...+436\\\\34-25=9\\43-34=9\\52-43=9\\\\\text{It's an arithmetic series.}\ a_1=25,\ d=9.\\\\\text{The formula for the n-th term of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\\text{Substitute:}\\\\a_n=25+(n-1)(9)\\a_n=25+9n-9\\a_n=9n+16\\\\\text{Calculate which the term of arithmetic series is the number 439.}\\\text{Put}\ a_n=439:\\\\9n+16=439\qquad\text{subtract 16 from both sides}\\9n=423\qquad\text{divide both sides by 9}\\n=47$

$\text{Therefore we have the series in summation notation:}\\\\\sum\limits_{n=1}^{47}(9n+16)\\\\\text{For calculation of the sum we use the formula of a sum of terms}\\\text{of an arithmetic sequence:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\text{Substitute}\ n=47,\ a_1=25,\ a_{47}=439:\\\\S_{47}=\dfrac{25+439}{2}\cdot47=\dfrac{464}{2}\cdot47=232\cdot47=10904\\\\\sum\limits_{n=1}^{47}(9n+16)=10,904$

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$4.\\12+24+48+...\\\\24:12=2\\48:24=2\\\\\text{It's\ a\ geometric series}\ a_1=12,\ r=2.\\\\\text{The formula for the n-th term of a geometic sequence:}\\\\a_n=a_1r^{n-1}\\\\\text{Substitute:}\\\\a_n=(12)(2^{n-1})\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\a_n=(12)\left(\dfrac{2^n}{2^1}\right)\\\\a_n=(6)(2^n)\\\\\text{The summation notation:}\\\\\sum\limits_{n=1}^\infty\bigg(6(2^n)\bigg)\\\\\text{The sum not exist, because}\ r>1,\ \text{therefore}\ 6(2^n)\to\infty$

6 0

3 years ago

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Arrange the given numbers in descending order 4/5,0.09,4,9,2/4

egoroff_w [7]

Answer:

9,4,4/5,2/4,0.09

Step-by-step explanation:

Simple, countdown from 9.

5 0

2 years ago

Read 2 more answers

Please solve this question

Svetach [21]

The best answer is 26 and can you
Mark brainliest or you need to find the sum

3 0

3 years ago

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Denelle is decorating a ballroom ceiling with garland. If the rectangular ceiling is 63 feet by 60 feet, how much garland will D

AURORKA [14]

Answer:

The answer to your question is: 3780 m²

Step-by-step explanation:

Data

Rectangular ceiling

base = 63 ft

height = 60 ft

Formula

Area = base x height

Process

Area = 63 x 60

= 3780 m²

7 0

3 years ago

A square mosaic is made of small glass squares. If there are 196 small squares in the mosaic, how many are along an edge?

alexandr402 [8]

There would be 14 small glass squares along the edges of the square mosaic.

This is because 14 * 14 = 196, which means that if each side length was 14 squares, that the area of the square would contain 196 squares.

5 0

2 years ago