Question

How does the graph of y = 3x compare to the graph of y = 3–x?

Answer 1

Answer and explanation:

In this problem, we have two functions. Let's call the first functions as:

$y=f(x)=3x$

and the second function:

$y=g(x)=3-x$

So we can compare this functions as follows:

• f(x) has a positive slope while g(x) has a negative slope.

• f(x) passes through the origin of the system of coordinates while g(x) cuts the y-intercept at $y=3$

• g(x) has an x-intercept at $x=3$ while f(x) cuts the origin.

Answer 2

Answer:

Both graphs represent the equation of a line

Step-by-step explanation:

Both graphs represent the equation of a straight line with the equation:

y = mx + c

Where m = the slope of the line and

c = intercept

Comparing both equations to the equation of a line given above:

In the first equation y = 3x

The slope, m = 3 (Positive slope)and

Intercept, c = 0

In the equation y = 3 -x

the slope, m = -1 (negative slope)

Intercept, c = 3