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2 years ago

450 mistakes in 9 tests. How many mistakes per test?

Mathematics

2 answers:

JulsSmile [24]2 years ago

8 0

Answer:

Step-by-step explanation:

all you have to do is Divide 9 ÷ 450 the answer is 50.

50 mistake per tests.

MAVERICK [17]2 years ago

8 0

Answer:

50 mistakes per test. 450 mistakes divided by 9 tests =50

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nalin [4]

I think it would be B

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3 years ago

Read 2 more answers

Find the missing angle. Show all your work. Pls, answer!

slega [8]

Steps:
(n-2) * 180 = sum of interior angles
(3-2) * 180 = 180

Bottom Triangle
25 + 51 + x = 180
x = 104

Top Triangle
104 + 34 + x = 180
x = 42

Answer:
42

7 0

2 years ago

10. Two sides of a triangle have

Oksanka [162]

I think the answer is 6 from the information you provided.

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3 years ago

Select whether each system of equations has no solution, one solution, or infinitely many solutions.

erik [133]

Answer:

one solution, no solution, infinitely many solutions

Step-by-step explanation:

I rearranged the first equation into x=6-2y

plug that into the second equation

2(6-2y)-3y=26

12-4y-3y=26

12-7y=26

-7y=14

y=-2

Then you plug that into one of the equations

x+2(-2)=6

x-4=6

x=10

The solution to the first system is (10,-2)

the second system already has one equation as something equal to a single variable so you just plug that into the other one

4x-2(2x-4)=-6

4x -4x +8 =-6

8=-6

this is a false statement so the system of equation has no solution

Lastly I rearranged the first equation into y=2x-4 and then plug that in

6x-3(2x-4)=12

6x-6x+12=12

12=12

this statement is true so the system of equations has infinite solutions

5 0

3 years ago

Help please<3 for all questions with solutions plz

antiseptic1488 [7]

Answer:

a) $h = -\frac{7}{4}$ , b) $h = f\,\circ\,g (-5) = \frac{3}{2}$ , c) $h = g\,\circ\,f (-2) = \frac{3}{8}$

Step-by-step explanation:

We proceed to solve each exercise below:

a) $f(-2) +3\cdot g(0)$

$h = \frac{2\cdot (-2)}{3\cdot (-2)+5}+3\cdot \left(\frac{3}{0+4} \right)$

$h = \frac{-4}{-6+5} +3\cdot \left(\frac{3}{4} \right)$

$h = -4+\frac{9}{4}$

$h = \frac{-16+9}{4}$

$h = -\frac{7}{4}$

b) $h = f\,\circ \,g (-5)$

$h = f\,\circ\,g (x) = \frac{\frac{6}{x+4} }{\frac{9}{x+4}+5 }$

$h = f\,\circ\,g (x)= \frac{\frac{6}{x+4} }{\frac{9+5\cdot (x+4)}{x+4} }$

$h = f\,\circ\,g (x) = \frac{6}{29+5\cdot x}$

$h = f\,\circ\,g (-5) = \frac{6}{29+5\cdot (-5)}$

$h = f\,\circ\,g (-5) = \frac{3}{2}$

c) $h = g\,\circ\,f(-2)$

$h = g\,\circ \, f (x) = \frac{3}{\frac{2\cdot x}{3\cdot x + 5} + 4 }$

$h = g\,\circ\,f (x) = \frac{3}{\frac{2\cdot x +4\cdot (3\cdot x +5)}{3\cdot x +5 } }$

$h = g\,\circ \,f (x) = \frac{3\cdot (3\cdot x +5)}{2\cdot x +12\cdot x +20}$

$h = g\,\circ\,f(x) = \frac{9\cdot x +15}{14\cdot x +20}$

$h = g\,\circ\,f(-2) = \frac{9\cdot (-2)+15}{14\cdot (-2)+20}$

$h = g\,\circ\,f (-2) = \frac{-3}{-8}$

$h = g\,\circ\,f (-2) = \frac{3}{8}$

6 0

2 years ago