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const2013 [10]
2 years ago
13

Can someone solve 5x − 7 = 13 step by step

Mathematics
2 answers:
RUDIKE [14]2 years ago
8 0

Answer:

x=4

Step-by-step explanation:

5x-7=13

5x=13+7

5x=20

x=20/5

x=4

Liula [17]2 years ago
7 0

Answer:

x = 4

Step-by-step explanation:

5x - 7 = 13

add 7 to both sides:

5x - 7 + 7 = 13 + 7

5x = 20

divide both sides by 5

\frac{5x}{5} = \frac{20}{5}

x = 4

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So, if we want the product of these two factors to be zero, at least one of them has to be zero.

The first factor is zero if

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Help me class8 (surds)​
Mashcka [7]

Answer:

  • \cfrac{991\sqrt{2} }{80}

Step-by-step explanation:

For a start simplify each of the roots:

  • \sqrt{72} =\sqrt{36*2} =6\sqrt{2}
  • \sqrt{50} =\sqrt{25*2} =5\sqrt{2}
  • \sqrt{128} =\sqrt{64*2} =8\sqrt{2}
  • \sqrt{98} =\sqrt{49*2} =7\sqrt{2}

Now simplify the expression in steps:

\sqrt{72}-\cfrac{48}{\sqrt{50} }  -\cfrac{45}{\sqrt{128} }  +2\sqrt{98} =

6\sqrt{2}-\cfrac{48}{5\sqrt{2} }  -\cfrac{45}{8\sqrt{2} }  +2*7\sqrt{2} =

6\sqrt{2}-\cfrac{48*8+45*5}{5*8\sqrt{2} }  +14\sqrt{2} =

20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =

20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =

20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =

20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =

\sqrt{2} (20-7\cfrac{49}{80} )=

\sqrt{2} *12\cfrac{31}{80} =

\cfrac{991\sqrt{2} }{80}

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