4 years ago

How do you solve 10+5(3x-4)=2x+7

Mathematics

1 answer:

Taya2010 [7]4 years ago

4 0

Answer:

$x=1\dfrac{4}{13}$

Step-by-step explanation:

Given the equation

$10+5(3x-4)=2x+7$

Use distributive property:

$10+5\cdot 3x-5\cdot 4=2x+7\\ \\10+15x-20=2x+7$

Use commutative property to rewrite the equation:

$15x+10-20=2x+7$

$15x-10=2x+7$

Add 10 th both sides:

$15x-10+10=2x+7+10\\ \\15x=2x+17$

Subtract $2x:$

$15x-2x=2x+17-2x\\ \\13x=17$

Divide by 13:

$x=\dfrac{17}{13}=1\dfrac{4}{13}$

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The answer is

<h2> $\sqrt{41} \: \: or \: \: \: 6.403 \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

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From the question the points are

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$\sqrt{41} \: \: or \: \: \: 6.403 \: \: \: units$

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