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Darina [25.2K]
3 years ago
6

Can someone explain these to me?

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
4 0

Answer:

Question 2: 4^12

Question 3: (9/64x)^11

Step-by-step explanation:

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Which graph represents the line y=−3x+4?
harkovskaia [24]

Answer:

x=4/3

Step-by-step explanation:

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A city planner wants to build a road perpendicular to D Street. What is the slope of the new road?
Romashka-Z-Leto [24]

Answer:

The slope of the new road is 0.

Step-by-step explanation:

  • the slope of d street line is tan(90)

[if the angle made by a line with x axis is \alpha then, the slope of that line will be tan(\alpha) ]

  • here, the angle made by the d street line with x axis is 90 degrees.
  • if a road is to be built which is perpendicular to d street , it should make 0 degrees i.e, it should be parallel to x axis .
  • so, the slope of new road will be tan(0) = 0
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3 years ago
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900 + 8 + 0.9 + 0.06 + 0.007
photoshop1234 [79]

Answer:

908.967

Step-by-step explanation:

i hope this helps :)

5 0
3 years ago
45.3297 rounded to the nearest tenth would be?
Alex
45.3297 rounded to the nearest tenth is 45.3
3 is in the tenths place, so you look at the number to the right of it. If that number is 5 or more, you round up. If the number is 4 or less, you round down. So you round 45.3297 down to 45.3
5 0
4 years ago
A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a
natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, .   .   .  , x₂₃ be the actual data observed by the student

The sample means  = x₁  +  x₂  +  .   .   .  , x₂₃ / 23

= \frac{x_1 +x_2 +...x_2_3}{23}

= 2.3hr

⇒\sum xi =2.3 \times 23 = 52.9hrs

let x₁ , x₂, .   .   .  , x₂₃  arranged in ascending order

Then x₂₃ was 10  and has been changed to 14

i.e x₂₃ increase to 4

Sample mean  = \frac{x_1 +x_2 +...x_2_3}{23}

\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47

therefore, the new sample mean is 2.47

2) For the old data set

the median is x_1_2(th) values

[\frac{n +1}{2} ]^t^h value

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = [{x_1_2]^t^h value remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)

The new sample standard sample deviation is calculated as

= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)

Now, when we compare (1) and (2)  the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)²  ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0
3 years ago
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