Question

Write the expression 44(4–7)(4) using a single exponent.

Answer 1

The given expression as single exponent is:

$4^4 \times 4^{-7} \times 4 = 4^{-2}$

Solution:

Given expression is:

$4^4 \times 4^{-7} \times 4$

In exponents,

When the base is same, exponents can be added

Which means,

$a^m \times a^n = a^{m+n}$

Therefore,

$4^4 \times 4^{-7} \times 4 = 4^{4-7+1}\\\\Simplify\\\\4^4 \times 4^{-7} \times 4 = 4^{-3+1} \\\\4^4 \times 4^{-7} \times 4 = 4^{-2}$

Thus the given expression as single exponent is:

$4^4 \times 4^{-7} \times 4 = 4^{-2}$

Answer 2

Answer:

D). 4^-2

Step-by-step explanation:

Just did it on edge.