Question

In a certain Algebra 2 class of 27 students, 5 of them play basketball and 12 of them play baseball. There are 2 students who play both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?

Answer 1

Answer:

$p= \frac{22}{27} =0.814 = 81.4%$

Step-by-step explanation:

Answer 2

Answer:  15/27

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Explanation:

• A = number of people who play basketball only
• B = number of people who play baseball only
• C = number of people who play both sports

5 play basketball, 2 play both, which means 5-2 = 3 play basketball only. So  A = 3.

12 play baseball, 2 play both, which means 12-2 = 10 play baseball only. So we have B = 10.

We have A+B+C = 3+10+2 = 15 people who play one sport, or the other, or both. This is out of 27 total. So that's what leads us to the answer 15/27.