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Masja [62]
3 years ago
9

Find the GCF for the pair 4, 49. ​

Mathematics
1 answer:
IgorC [24]3 years ago
6 0
I believe the GCF for the park 4 and 49 is 1.
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The passing yards for the top 5 quarterbacks in the country are 3,832, 3,779, 3,655, 3,642, and 3,579. Find the variance and sta
Leviafan [203]

First get the average passing yards:

(3,832 + 3,779 + 3,655 + 3,642 + 3,579) / 5 = 3,697.4

Now get the squared residuals for each quarterback's passing yards. That is, compute the difference between each data and the average, then square the result. For example,

(3,832 - 3,697.4)^2 = 134.6^2 = 18,117.2

For the others, you should get squared residuals of

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1,797.76

3,069.16

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Take the sum of the squared residuals, then - since this is a sample, and not a population of all quarterbacks - divide the sum by 5 - 1 = 4 to get the variance:

(18,117.2 + 6,658.56 + 1,797.76 + 3,069.16 + 14,018.6)/4 = 10,915.3

The standard deviation is just the square root of the variance:

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5 0
3 years ago
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Alexandra [31]

Answer:

Original price of car = $20,000

Step-by-step explanation:

Let the original price of the car be 'x' dollars.

Given:

Here, the depreciation of the car is occuring exponentially as the value depreciates to half in every four years.

Worth of car after 8 years = $5000

Value after depreciation in 4 years = Half of original value = \frac{x}{2}

So, value of car after depreciation in another 4 years = Half of the value after 4 years = \frac{1}{2}(\frac{x}{2})=\frac{x}{4}

Therefore, final depreciated value after 8 years is \frac{x}{4}.

But, as per question, final depreciated value is $5000. Thus,

\frac{x}{4}=5000\\x=5000\times 4\\x=20000

Therefore, the original price of the car was $20,000.

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Answer:

A. x≥4 ( red on 4)

B. x≤4 ( red on 4)

C. x>4 (blue on 4)

D. x<4 (blue on 4)

Step-by-step explanation:

illustrated

A. x≥4 ( red on 4)

B. x≤4 ( red on 4)

C. x>4 (blue on 4)

D. x<4 (blue on 4)

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Keith_Richards [23]
Least to greatest: cups, pints, quarts, gallons
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Answer:

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Step-by-step explanation:

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