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Masja [62]
3 years ago
9

Find the GCF for the pair 4, 49. ​

Mathematics
1 answer:
IgorC [24]3 years ago
6 0
I believe the GCF for the park 4 and 49 is 1.
You might be interested in
<img src="https://tex.z-dn.net/?f=4%28a%20%2B%202%20%29%20-%202%20%28a%20-%203%29" id="TexFormula1" title="4(a + 2 ) - 2 (a - 3)
satela [25.4K]

Answer:

\large\boxed{2a+14}

Step-by-step explanation:

4(a + 2 ) - 2 (a - 3)\qquad\text{use distributive property:}\ a(b+c)=ab+ac\\\\=4a+8-2a-(-6)\qquad\text{combine like terms}\\\\=(4a-2a)+(8+6)\\\\=2a+14

5 0
3 years ago
Chris is riding her bike for 10 miles. She averages 12 mi/h. how many more minutes must she ride before she travels 60 miles?
madam [21]

Answer:

5 Minutes

take 10 and add 12 for each minute until you pass 60

3 0
3 years ago
How many cups are in 3 gallons? 1 gallon = 16 cups<br><br> Label your answer in cups.
shepuryov [24]

Answer:

48 cups

Step-by-step explanation:

16 times 3

7 0
3 years ago
Read 2 more answers
Which two statements are missing in steps 3 and 4?
Snezhnost [94]

Answer:

∠B ≅ ∠Y △ABC ~ △ZYX by the SAS similarity theorem.

Step-by-step explanation:

1. AB=6 units

YZ=3 units

BC=8 units

XY=4 units, then

\dfrac{AB}{ZY}=\dfrac{BC}{YX}=2

2. \angle B and \angle Y are right angles - given

3.  \angle B\cong \angle Y two right angles are always congruent.

4. \triangle ABC\sim \triangle ZYX by SAS similarity theorem.

SAS Similarity Theorem states that if two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar.

4 0
3 years ago
Read 2 more answers
Help with the following problem please
Effectus [21]
Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5

By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1

Area of outer circle                  = \pi R^2=\pi7^2=49\pi
Area of large shaded circle      = \pi x^2=\pi5^2=25\pi
Area of 4 small shaded circles = 4\pi r^2=4\pi1^2=4\pi
Total area of shaded circles     =25\pi+4\pi=29\pi

Shaded area as a fraction of that of the outer circle 
=\frac{29\pi}{49\pi}=29/49

3 0
3 years ago
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