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Bond [772]
4 years ago
14

A mother who is 40 years old has a daughter and a son. The son is twice as old as the daugther. In 15 years the sum of all their

ages will be 100 years. How old are the siblings now?
Mathematics
2 answers:
Verizon [17]4 years ago
8 0

Answer:

son = 10

daughter  = 5

Step-by-step explanation:

Let the daughter = d

Let the son =          s

s = 2*d

there ages in 15 years

Mother = 40 + 15 = 55

Son = s + 15

daughter = d + 15

Total: s + 15 + d+15 + 55 = 100    Combine the like terms.

s + d + 85 = 100                            Subtract 85 from both sides.

s + d = 100 - 85

s + d = 15

s = 2*d                                            Substitute for son

2d + d = 15

3d = 15

d = 15/3

d = 5

son = 2*5

son = 10

Check

son = 15 =           25

daughter + 15 =  20

<u>Mother + 15    =   55</u>

Total                   100 just as it should be.

alisha [4.7K]4 years ago
4 0

Answer:

Step-by-step explanation:

Let's call the ages D for daughter and S for son.

We know that the son is twice as old as the daughter, so:

S = 2D

We also know that in 15 years, their ages add up to 100, so:

(40+15) + (S+15) + (D+15) = 100

55 + S + 15 + D + 15 = 100

85 + S + D = 100

S + D = 15

Substituting the first equation:

2D + D = 15

3D = 15

D = 5

Therefore:

S = 2D = 10

The son is 10 and the daughter is 5.

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Step-by-step explanation:

4⁰ = 1, 1st term

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4⁶ = 4096, 7th term

Answered by GAUTHMATH

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3 years ago
The math says expand 5(2-7x) what is the answer
kow [346]

Step-by-step explanation:

in my opinion

5(2- 7x)

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= 10-35x

8 0
3 years ago
1. Write an algebra equation for each purchase. I (Mickey) bought an ice cream treat and a bottle of water for $10. Pam purchase
Ne4ueva [31]

x+y=10

x+2y=14
x is common in both so u have to subtract the second one from 1st
x-x + y-2y = 10-14
-y = -4
y=4
which means bottle of water (y) = 4
and then substitute 4 in equation (x+y=10 or x+2y=10)
x + 4 = 10
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5 0
3 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
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Mariulka [41]
I think it wold be b

please tell me if i wrong
4 0
3 years ago
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