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Hunter-Best [27]
2 years ago
9

The angle lies in Quadrant II. sin0=3/4 What is cos 0?

Mathematics
1 answer:
klio [65]2 years ago
5 0

Answer:

cosФ is -\frac{\sqrt{7}}{4}  ⇒ B

Step-by-step explanation:

Let us solve the question using one of the identities of trigonometry

∵ sin²Ф + cos²Ф = 1

∵ sinФ = \frac{3}{4}

→ Substitute it in the rule above to find cos Ф

∴ (\frac{3}{4})² + cosФ² = 1

∴ \frac{9}{16} + cosФ² = 1

→ Subtract \frac{9}{16}  from both sides

∴ cos²Ф = \frac{7}{16}

→ Take √ for both sides

∴ cosФ = ± \frac{\sqrt{7}}{4}

∵ Angle Ф lies on the second quadrant

∴ cosФ is a negative value

∴ cosФ = -\frac{\sqrt{7}}{4}  

∴ cosФ is -\frac{\sqrt{7}}{4}  

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Answer:

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Step-by-step explanation:

Given

f(x)=5x^2+9x-2

Remainder theorem states that when f(x) is divided by x-a then the remainder can be calculated by calculating f(a).

Now Using the remainder theorem to divide 5x^2+9x-2 by x+3 to find the remainder:

f(x)=5x^2+9x-2

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