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olga2289 [7]
3 years ago
15

Which expression is NOT equal to 729? 3 × 3 × 3 × 3 × 3 × 3 6,3 9 × 9 × 9 36

Mathematics
1 answer:
suter [353]3 years ago
8 0

Answer:

Rewrite as an equation.

log

9(729)=x

Rewrite

log

9(729)=x

in exponential form using the definition of a logarithm. If

x and b

are positive real numbers and b

does not equal 1, then log b(x)=y is equivalent to by=x. 9x=729

Create expressions in the equation that all have equal bases.

(32)x=3

Rewrite

(32)x as 32x. 32x=36

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

2 x 3=6

Solve for

x.x=3

The variable  x

is equal to

3.3

Step-by-step explanation:

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Answer: If you are solving the Function Operation, the answer will be 17x-2.

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Hope this helps you out. If not, comment and let me know what you are looking for/needing/wanting. Good luck, mate! ☺

7 0
3 years ago
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A ladder 10 m long,leans against a vertical wall at an angle of 70° to the ground.if the ladder slips down the wall 4m,find,corr
lina2011 [118]

Answer:

(a) the new angle the ladder makes with the ground is 32.7^o

(b) the ladder slipped back about 5 meters

Step-by-step explanation:

Notice that the ladder doesn't change its length in the process.

So let's start from the initial situation , finding the distance from the ground at which the ladder touches the wall when the angle with the ground is 70^o. Notice that this situation is represented by a right angle triangle with the right angle between the wall and the ground (see attached image), and that we can use the sine function to find the side opposite to the 70 degree angle:

sin(70^o)=\frac{opposite}{hypotenuse} \\sin(70^o)=\frac{h}{10}\\h=10\, sin(70^o) \approx 9.4 \,\,m

therefore 9.4 meters is approximately the height at which the ladder touches the wall initially.

Now, if the tip of the ladder goes down the wall 4 meters, it is now at 9.4 m - 4 m = 5.4 m from the ground. We can therefore use again the sine function to solve for the new angle:

sin(x)=\frac{opposite}{hypotenuse} \\sin(x)=\frac{5.4}{10} \\sin(x)=0.54\\x=arcsin(0.54)\\x= 32.7^o

To answer the second question we need to find the original distance from the wall that the bottom of the ladder was originally, and for that we can use the cosine function:

cos(70^o)=\frac{adjacent}{hypotenuse} \\cos(70^o)=\frac{x}{10}\\x=10\,cos(70^o)\\x\approx 3.4  \,\,m

Now fro the new position of the bottom of the ladder relative to the wall:

cos(32.7^o)=\frac{adjacent}{10} \\adjacent=10\,cos(32.7^o)\\adjacent\approx 8.4\,\,m

then the difference in between those two distances is what we need:

8.4 m - 3.4 m = 5 m

4 0
3 years ago
If 6x + 5y = 10, what is y in terms of x?<br> Please include an explanation!
Mnenie [13.5K]

what you're trying to do is form an equation for y

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y = - 6x/5 + 10/5

y = - 6x/5 + 2

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2 years ago
Which fraction is equivalent to 12/27? help
Mkey [24]

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<h3>Hope This Helps You</h3>
7 0
3 years ago
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Please answer this question !! BRAINLIEST !!
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Cos inverse0.7813

=38.6°

B

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