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MaRussiya [10]
3 years ago
6

1. Names and Faces

Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Answer:

sdhhciufdhsuhucshduhcudsh  uhhuhu u uuhuhuhc usdh uchsduhc dsuc dsu cu dc

Step-by-step explanation:

chudhyuherhfuryhfruhruhgyr gt tttggtg  gtgg

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alexira [117]
<em><u>There is no solution!</u></em>
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3 years ago
You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

2\theta = \cos^{-1}0

\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

6 0
3 years ago
The ordered pairs (12,32), (x,40), (18,48), (21,y) represent a proportional relationship. Find the values of x and y.
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Answer:

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3 years ago
What is the slope of the line that passes through the points (-2,3) and (-14, -5)?
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Slope = 2/3 (positive 2/3)
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Answer:

the distance is 4

Step-by-step explanation:

7 0
2 years ago
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