Answer:
The answer is 7
Step-by-step explanation:
We know than Tan45=1
Tanx=opp/adj
tan45=y/(7
)/2
Thus y=7
/2
We know by pythagoras theorem that hyp^2=side^2+side^2
=(
+
=(49(2)/4)+(49(2)/4)
=(49/2)+(49/2)
=(98/2)
=49
x=7
<em>♥️</em><em>Hello</em><em> </em><em>♥️</em>
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<em>@</em><em>MorbidAngella</em><em> </em>
Answer:

Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean for the sample
population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
(1)
For this case the confidence interval is given by (6.55,8.15). And we can estimate the margin of error with this formula since the confidence interval is symmetrical:

Answer:
a. the cost of the t-shirt
b. x+12=34
c. x=22
d. t-shirt cost 22$
Answer:
Percentage of free time Gary spends on playing video games and using internet = 54.29%
Step-by-step explanation:
Given:
Gary spends 10 hours per week on the internet.
Gary spends 9 hours per week on video games.
Gary has 5 hours free time per day.
To find the percentage of free time Gary is using to play video game and use the internet.
Solution:
Total number of hours of free time Gary has per week = 
<em>[As there are 7 days in a week so we multiply by 7]</em>
Total number of hours of free time Gary spends on playing video games and using internet per week =
Percentage of free time Gary spends on playing video games and using internet per week can be calculated as :
⇒
⇒ 
⇒ 54.29% (Answer)