5 miles high is one of the sides of a triangle depending on accuracy level
h^2=x^2+y^2
we don't have 2 distances
Tan A=O/a
O=a tan A
We solve for O because the angle is at the top of the line going up and we want the opposite angle that is along the ground
O=5×tan(173.7/2)=90.854033512
The distance he can see is:
90.85*2~181.7 miles
Now we need to find the distance between lines:
The north south distance between each line is 69 miles
thus the number of degrees he will see will be:
181.7/69
=2 19/30
1. AD/DB=CE/EB
given
2. AD/DB+1=CE/EB+1
Addition Property of Equality
3. AD+DB/DB=CE+EB/EB
using common denominators
4. AB = AD + DB
CB = CE + EB
segment addition
5. AB/DB=CB/EB
Substitution Property of Equality
6.ABC DBE
Reflexive Property of Congruence
7. ABC ~ DBE
SAS similarity criterion
<span>8. </span>
Corresponding angles of similar triangles are congruent.
9. DE|| AC
<span>If the corresponding angles formed by </span>
Answer:
The answer is J
Step-by-step explanation:
If you start from Quinn's location (8,7), and move south 3 units, you get to (8,4). Then you move to the west 4 units and that gets you to (4,4).
hope this helped! :)
Answer:
The answer is 12.4
Step-by-step explanation:
Because it is this way.
Answer:14
Step-by-step explanation: